X ---> X/C
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@ -834,9 +834,8 @@ Let $X$ be a curve with an action of $G$ and write $Y := X/H$. For any $k[C]$-mo
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is determined by higher ramification data as well.
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\end{proof}
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%
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\section{Examples}
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%
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Assume that $G$ is a group with a normal $p$-Sylow subgroup $H$ of order~$p$. Let $C := G/H$. Then $G = H \rtimes_{\chi} C$
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The method of proof of Main Theorem allows to obtain explicit formulas in the style of the result of Chevalley--Weil for
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particular group. Assume that $G$ is a group with a normal $p$-Sylow subgroup $H$ of order~$p$. Let $C := G/H$. Then $G = H \rtimes_{\chi} C$
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for a homomorphism $\chi : C \to \FF_p^{\times}$.
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%
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\begin{Proposition}
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@ -864,9 +863,14 @@ $a_W'$ is as in the equality~\eqref{eqn:cw} for the action of $C$ on $Y := X/H$
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for some $A_W, B_W \in \ZZ$. ??
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\end{proof}
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%
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Let $p > 2$ be a prime and $p \nmid m$ an natural number. Fix a primitive root of unity $\zeta \in \ol{\FF}_p^{\times}$ of order $m \cdot (p-1)$.
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\section{An example -- a superelliptic curve with a metacyclic action}
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%
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Let $p > 2$ be a prime and $p \nmid m$ an natural number. Let $k$ be an algebraically closed field of characteristic~ $p$.
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Fix a primitive root of unity $\zeta \in \ol{\FF}_p^{\times}$ of order $m \cdot (p-1)$.
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Note that $\zeta^m \in \FF_p$.
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We compute now the equivariant structure of the de Rham cohomology for the superelliptic curve $X$ with the affine part given by:
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In this section we compute the equivariant structure of the de Rham cohomology for the superelliptic curve $X$ with the affine part given by:
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%
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\begin{equation*}
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y^m = x^{p^n} - x.
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@ -887,24 +891,80 @@ This action is given by:
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\rho(x, y) &= (\zeta^m \cdot x, \zeta \cdot y).
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\end{align*}
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%
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\begin{Proposition}
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\[
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H^1_{dR}(X) \cong ????.
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\]
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\end{Proposition}
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%
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Note that $X/G \cong \PP^1$ and the quotient map is given by $(x, y) \mapsto (x^p - x)^{p-1}$. Indeed, ????.
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We claim that the set of branch points is given by $B := \{ 0, \infty \} \cup B'$, where
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We claim that the set of branch points is given by $B := \{ Q_{\infty}, Q_0, Q_1, \ldots, Q_N \}$, where
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$N := \frac{p^{n-1} - 1}{p - 1}$, $Q_0 = 0$, $Q_{\infty} = \infty$ and $Q_1, \ldots, Q_N$ are
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the elements of the set
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%
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\[
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B' := \{ (\alpha^p - \alpha)^{p-1} : \alpha \in \FF_{p^n} \setminus \FF_p \}.
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\{ (\alpha^p - \alpha)^{p-1} : \alpha \in \FF_{p^n} \setminus \FF_p \}.
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\]
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%
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The set $B'$ has $\frac{p^{n-1} - 1}{p - 1}$ elements. We claim that:
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Write $C' := \langle \rho^{p-1} \rangle \cong \ZZ/m$ and note that $C'$ is in the center of $G$. We claim that:
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%
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\begin{itemize}
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\item $G_{Q_0} = C$,
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\item $G_{Q_0}$ is the conjugacy class of the subgroup $C$,
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\item $G_Q = \langle \rho^{p-1} \rangle \cong \ZZ/m$ for $Q \in B'$,
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\item $G_{Q_{\infty}} = G$ and the lower ramification jump at $Q_{\infty}$ equals $m$,
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\item $G_{Q_{\infty}} = G$ and the lower ramification jump at $Q_{\infty}$ equals $m$.
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\item $G_{Q_i} = C'$ for $i = 1, \ldots, N$.
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\end{itemize}
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%
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Indeed, ????.
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Indeed, ????. The ramification points of $\pi : X \to X/G$ are as follows:
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%
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\begin{itemize}
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\item points $P_0^{(1)}, \ldots, P_0^{(p)}$ above $Q_0$
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\item[] (their stabilizers are subgroups $C_1 = C$, $\ldots$, $C_p$
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conjugated to $C$),
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\item point $P_{\infty}$ above $Q_{\infty}$ (its stabilizer is $G$),
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\item points $P_i^{(1)}, \ldots, P_i^{(p \cdot (p-1))}$ above $Q_i$ for $i = 1, \ldots, N$
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\item[] (their stabilizers equal $C'$).
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\end{itemize}
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%
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The same points are in the ramification locus of the morphism $X \to X/C$ with the following
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ramification groups:
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%
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\begin{align*}
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C_{P_0^{(1)}} &= C\\
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C_{P_0^{(i)}} &= C' \qquad \textrm{ for } i > 1,\\
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C_{P_{\infty}} &= C\\
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C_{P_i^{(j)}} &= C' \qquad \textrm{ for } i = 1, \ldots, N, \, j = 1, \ldots, p \cdot (p-1).
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\end{align*}
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Note that $Y := X/H$ is given by the equation:
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%
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\[
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y^m = z^{p^{n-1}} + \ldots + z^p + z.
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\]
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%
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Let $\psi : C \to k^{\times}$ be a primitive character. We claim that:
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%
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\begin{align*}
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a^{dR}_{X, C}(\psi^i) &=
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\begin{cases}
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p \cdot N, & \textrm{ if } m \nmid i,\\
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0, & \textrm{ otherwise. }
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\end{cases}\\
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a^{dR}_{Y, C}(\psi^i) &=
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\begin{cases}
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\frac{p^{n-1} - 1}{p - 1}, & \textrm{ if } m \nmid i,\\
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0, & \textrm{ otherwise. }
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\end{cases}
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\end{align*}
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%
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%
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