447 lines
15 KiB
TeX
447 lines
15 KiB
TeX
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%\usepackage{refcheck}
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\numberwithin{equation}{section}
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\hyphenation{Woj-ciech}
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%opening
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\begin{document}
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\title[The de Rham...]{?? The de Rham cohomology of covers\\ with cyclic $p$-Sylow subgroup}
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\author[A. Kontogeorgis and J. Garnek]{Aristides Kontogeorgis and J\k{e}drzej Garnek}
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\address{???}
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\email{jgarnek@amu.edu.pl}
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\subjclass[2020]{Primary 14G17, Secondary 14H30, 20C20}
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\keywords{de~Rham cohomology, algebraic curves, group actions,
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characteristic~$p$}
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\urladdr{http://jgarnek.faculty.wmi.amu.edu.pl/}
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\date{}
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\begin{abstract}
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????
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\end{abstract}
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\maketitle
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\bibliographystyle{plain}
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%
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\section{Introduction}
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%
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\begin{mainthm}
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Suppose that $G$ is a group with a $p$-cyclic Sylow subgroup.
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Let $X$ be a curve with an action of~$G$ over a field $k$ of characteristic $p$.
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The $k[G]$-module structure of $H^1_{dR}(X)$ is uniquely determined by the lower ramification groups and the fundamental characters of closed
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points $x$ of $X$ that are ramified in the cover $X \to X/G$.
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\end{mainthm}
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\section{Cyclic covers}
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%
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Let for any $\ZZ/p^n$-cover $X \to Y$
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%
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\begin{align*}
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u_{X/Y, P}^{(t)} &:= \min \{ t \ge 0 : G_P^{(t)} \cong \ZZ/p^{n-t} \},\\
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l_{X/Y, P}^{(t)} &:= \min \{ t \ge 0 : G_{P, t} \cong \ZZ/p^{n-t} \}.
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\end{align*}
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%
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Note that if $G_P = \ZZ/p^n$, this coincides with the standard definition of
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the $t$th upper (resp. lower) ramification jump of $X \to Y$ at $P$.
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%
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\begin{Theorem} \label{thm:cyclic_de_rham}
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Suppose that $\pi : X \to Y$ is a $\ZZ/p^n$-cover. Let $\langle G_P : P \in X(k) \rangle = \ZZ/p^m = G_{P_0}$ for $P_0 \in X(k)$. Then, as $k[\ZZ/p^n]$-modules:
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%
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\[
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H^1_{dR}(X) \cong J_{p^n}^{2 (g_Y - 1)} \oplus J_{p^n - p^{n-m} + 1}^2 \oplus \bigoplus_{P \neq P_0} J_{p^n - p^n/e_P}^2
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\oplus \bigoplus_P \bigoplus_{t = 0}^{n-1} J_{p^n - p^t}^{u_{P}^{(t+1)} - u_{P}^{(t)}},
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\]
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%
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where $e_P := e_{X/Y, P}$ and $u_P^{(t)} := u_{X/Y, P}^{(t)}$.
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\end{Theorem}
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%
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Write $H := \langle \sigma \rangle \cong \ZZ/p^n$.
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For any $k[H]$-module $M$ denote:
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%
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\begin{align*}
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M^{(i)} &:= \ker ((\sigma - 1)^i : M \to M),\\
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T^i M &= T^i_H M := M^{(i)}/M^{(i-1)} \quad \textrm{ for } i = 1, \ldots, p^n.
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\end{align*}
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%
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Recall that $\dim_k T^i M$ determines the structure of $M$ completely (cf. ????).
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In the inductive step we use also the group $H' := \ZZ/p^{n-1}$. In this case
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we denote the irreducible $k[H']$-modules by $\mc J_1, \ldots, \mc J_{p^{n-1}}$
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and $\mc T^i M := T^i_{H'} M$ for any $k[H']$-module $M$.\\
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Note also that for $j \ge 1$:
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%
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\[
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l_{X/Y, P}^{(j)} - l_{X/Y, P}^{(j-1)} = \frac{1}{p^{j-1}} (u_{X/Y, P}^{(j)} - u^{(j-1)}_{X/Y, P})
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\]
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%
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(in particular, $u_{X/Y, P}^{(1)} = l_{X/Y, P}^{(1)}$). Moreover, if $X' \to Y$ is the $\ZZ/p^N$-subcover of $X \to Y$ for $N \le n$ then:
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%
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\begin{itemize}
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\item $u_{X'/Y, P}^{(t)} = u_{X'/Y, P}^{(t)}$ for $t \le N$,
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\item $l_{X/X', P}^{(t)} = l_{X/X', P}^{(t + N)}$ for $t \le n-N$.
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\end{itemize}
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\begin{Lemma} \label{lem:G_invariants_\'{e}tale}
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If the $G$-cover $X \to Y$ is \'{e}tale, then the natural map
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%
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\[
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H^1_{dR}(Y) \to H^1_{dR}(X)^G
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\]
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%
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is an isomorphism.
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\end{Lemma}
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\begin{proof}
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????
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\end{proof}
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%
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\begin{Lemma} \label{lem:trace_surjective}
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If the $G$-cover $X \to Y$ is totally ramified, then the map
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%
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\[
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\tr_{X/Y} : H^1_{dR}(X) \to H^1_{dR}(Y)
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\]
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%
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is an epimorphism.
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\end{Lemma}
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\begin{proof}
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????
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\end{proof}
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%
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\begin{Lemma} \label{lem:TiM_isomorphism}
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For any $i \le p^n - 1$ we have the following $k$-linear monomorphism:
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%
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\[
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(\sigma - 1) : T^{i+1} M \hookrightarrow T^i M.
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\]
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\end{Lemma}
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\begin{proof}
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\end{proof}
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%
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\begin{Lemma} \label{lem:lemma_mcT_and_T}
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Let $M$ be a $k[H]$-module. Let $T^i M$ and $\mc T^i M$ be as above.
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If $\dim_k \mc T^i M = \dim_k \mc T^{i+1} M$ for some $i$ then:
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%
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\[
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\dim_k T^{pi + p} M = \dim_k T^{pi + p - 1} M = \ldots = \dim_k T^{pi - p + 1} M.
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\]
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\end{Lemma}
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\begin{proof}
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By Lemma~\ref{lem:TiM_isomorphism}:
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%
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\begin{align*}
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\dim_k \mc T^i M &= \dim_k T^{pi} M + \ldots + \dim_k T^{pi - p + 1} M\\
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&\ge \dim_k T^{pi+p} M + \ldots + \dim_k T^{pi+1} M
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= \dim_k \mc T^{i+1} M.
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\end{align*}
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%
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Since the left-hand side and right hand side are equal, we conclude by Lemma~\ref{lem:TiM_isomorphism}
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\end{proof}
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\begin{proof}[Proof of Theorem~\ref{thm:cyclic_de_rham}]
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We use the following notation: $H' := \langle \sigma^p \rangle \cong \ZZ/p^{n-1}$,
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$H'' := H/\langle \sigma^{p^{n-1}} \rangle \cong \ZZ/p^{n-1}$, $Y' := X/H'$, $X'' := X/H''$.
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Write also $\mc M := H^1_{dR}(X)$.
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We consider now two cases. If the cover $X \to Y$ is \'{e}tale, then by induction assumption, since $2(g_{Y'} - 1) = p \cdot 2 \cdot (g_Y - 1)$:
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%
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\[
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\mc M \cong \mc J_{p^{n-1}}^{2 p \cdot (g_Y - 1)} \oplus k^{\oplus 2}.
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\]
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%
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Therefore $\dim_k \mc T^2 \mc M = \ldots = \dim_k \mc T^{p^{n-1}} \mc M = 2 p (g_Y - 1)$,
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which by Lemma~\ref{lem:lemma_mcT_and_T} implies that
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%
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\[
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\dim_k T^p \mc M = \ldots = \dim_k T^{p^n} \mc M = 2(g_Y - 1).
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\]
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%
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Thus, for $i = 2, \ldots, p$:
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%
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\[
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\dim_k T^i \mc M \ge 2(g_Y - 1) = \dim_k T^{p+1} \mc M.
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\]
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%
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On the other hand, by Lemma~\ref{lem:G_invariants_\'{e}tale} we have
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%
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$
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\dim_k T^1 \mc M = 2 g_Y
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$. Thus:
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%
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\begin{align*}
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\sum_{i = 2}^p \dim_k T^i \mc M = 2g_X - \dim_k T^1 \mc M - \sum_{i = p+1}^{p^n} \dim_k T^i \mc M = (p-1) \cdot 2(g_Y - 1).
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\end{align*}
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%
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Thus $\dim_k T^i \mc M = 2(g_Y - 1)$ for every $i \ge 2$, which ends the proof in this case.
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Assume now that $X \to Y$ is not \'{e}tale. Therefore $X \to X''$ is also not \'{e}tale.
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By induction hypothesis for $H'$ acting on $X$, we have the following isomorphism of $k[H']$-modules:
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%
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\[
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\mc M \cong \mc J_{p^{n-1}}^{2 (g_{Y'} - 1)} \oplus \mc J_{p^{n-1} - p^{n - 1 -m'} + 1}^2 \oplus \bigoplus_{P \neq P_0} \mc J_{p^{n-1} - p^{n-1}/e'_P}^2
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\oplus \bigoplus_P \bigoplus_{t = 0}^{n-1} \mc J_{p^n - p^t}^{u_{X/Y', P}^{(t+1)} - u_{X/Y', P}^{(t)}}
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\]
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%
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where $e'_P := e_{X/Y', P}$ and
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%
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\[
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m' :=
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\begin{cases}
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n-1, & \textrm{ if } m = n,\\
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m, & \textrm{ otherwise.}
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\end{cases}
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\]
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%
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Therefore, for $i \le p^n - p^{n-1}$
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%
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\begin{align*}
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\dim_k \mc T^i \mc M =
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\begin{cases}
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???,
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\end{cases}
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\end{align*}
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%
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In particular, $\dim_k \mc T^1 \mc M = \ldots = \dim_k \mc T^{p^{n-1} - p^{n-2}} \mc M$.
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Thus by Lemma~\ref{lem:lemma_mcT_and_T}
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%
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\[
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\dim_k T^1 \mc M = \ldots = \dim_k T^{p^n - p^{n-1}} \mc M = \frac{1}{p} \dim_k \mc T^1 \mc M = ????.
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\]
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%
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By Lemma~\ref{lem:trace_surjective} since $X \to X''$ is not \'{e}tale, the map $\tr_{X/X''} : H^1_{dR}(X) \to H^1_{dR}(X'')$ is surjective. Recall that
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in $\FF_p[x]$ we have the identity:
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%
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\[
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1 + x + \ldots + x^{p-1} = (x - 1)^{p-1}.
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\]
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%
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Therefore in the group ring $k[H]$ we have:
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%
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\[
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\tr_{X/X''} = \sum_{j = 0}^{p-1} (\sigma^{p^{n-1}})^j = (\sigma^{p^{n-1}} - 1)^{p-1} =
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(\sigma - 1)^{p^n - p^{n-1}}.
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\]
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%
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This implies that:
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%
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\[
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\ker(\tr_{X/X''} : \mc M \to \mc M'') = \mc M^{(p^n - p^{n-1})}
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\]
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%
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and that $\tr_{X/X''}$ induces a $k$-linear isomorphism $T^{i + p^n - p^{n-1}} \mc M \to \mc T^i \mc M''$ for any $i \ge 1$. Thus:
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%
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\[
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\dim_k T^{i + p^n - p^{n-1}} \mc M = \dim_k \mc T^i \mc M'' = ....
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\]
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%
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This ends the proof.
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\end{proof}
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\section{Hypoelementary covers}
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%
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Assume now that $G = H \rtimes_{\chi} C = \langle \sigma \rangle \rtimes_{\chi} \langle \rho \rangle \cong \ZZ/p^n \rtimes_{\chi} \ZZ/c$.
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Let $X$ be a curve with an action of $G$ and write $Y := X/H$. For any $k[C]$-module $M$ and any character $\psi$ of $H$ we write $M^{\psi} := M \otimes_{k[G]} \psi$.
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%
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\begin{Proposition} \label{prop:main_thm_for_hypoelementary}
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Main Theorem holds for a hypoelementary $G$ as above and $k = \ol k$.
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\end{Proposition}
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%
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\begin{Lemma}
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Let $M$ be a $k[G]$-module of finite dimension. The $k[G]$-structure of $M$
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is uniquely determined by the $k[C]$-structure of $T^1 M, \ldots, T^{p^n} M$.
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\end{Lemma}
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\begin{proof}
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???
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\end{proof}
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%
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\begin{Lemma} \label{lem:N+Nchi+...}
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Let $N_1$, $N_2$ be $k[G]$-modules. Assume that for some $j$
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%
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\[
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N_1 \oplus N_1^{\chi} \oplus \ldots \oplus N_1^{\chi^j}
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\cong N_2 \oplus N_2^{\chi} \oplus \ldots \oplus N_2^{\chi^j}.
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\]
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%
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If $\GCD(j, p-1) = 1$, then $N_1 \cong N_2$.
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%If $p-1 | j$, then $N_1 \cong N_2^{\chi^i}$ for some $i$.
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\end{Lemma}
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\begin{proof}
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\end{proof}
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%
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\begin{Lemma} \label{lem:TiM_isomorphism_hypoelementary}
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For any $i \le p^n - 1$:
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%
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\[
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(\sigma - 1) : T^{i+1} M \hookrightarrow (T^i M)^{\chi^{-1}}.
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\]
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\end{Lemma}
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\begin{proof}
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\end{proof}
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\begin{proof}[Proof of Proposition~\ref{prop:main_thm_for_hypoelementary}]
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We prove this by induction on $n$. If $n = 0$, then it follows by Chevalley--Weil theorem.
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Consider now two cases. Firstly, we assume that $X \to Y$ is \'{e}tale.
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Recall that by proof of Theorem~\ref{thm:cyclic_de_rham}, the map $(\sigma - 1)$
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is an isomorphism of $k$-vector spaces between $T^{i+1} \mc M$ and $T^i \mc M$ for
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$i = 2, \ldots, p^n$. This yields an isomorphism of $k[C]$-modules for $i \ge 2$ by Lemma~\ref{lem:TiM_isomorphism_hypoelementary}:
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%
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\begin{equation} \label{eqn:TiM=T1M_chi_\'{e}tale}
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T^i \mc M \cong (T^2 \mc M)^{\chi^{-i+2}}
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\end{equation}
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%
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Observe that $\mc T^i \mc M$ has the filtration $\mc M^{(pi)} \supset \mc M^{(pi - 1)} \supset \ldots \supset \mc M^{(pi - p)}$ with subquotients $T^{pi} \mc M, \ldots, T^{pi - p} \mc M$.
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Thus, since the category of $k[C]$-modules is semisimple, for $i \le p^n - p^{n-1}$:
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%
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\begin{align*}
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\mc T^i \mc M &\cong
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\begin{cases}
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T^1 \mc M \oplus T^2 \mc M \oplus \ldots \oplus (T^2 \mc M)^{\chi^{-p + 1}}, & i = 1\\
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T^2 \mc M \oplus \ldots \oplus (T^2 \mc M)^{\chi^{-p}}, & i > 1.
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\end{cases}
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\end{align*}
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%
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Thus, since by induction hypothesis $\mc T^2 \mc M$ is determined by ramification data,
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we have by Lemma~\ref{lem:N+Nchi+...} that $T^2 \mc M$ is determined by ramification data.
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Moreover, by Lemma~\ref{lem:G_invariants_\'{e}tale} and induction hypothesis, $T^1 \mc M \cong H^1_{dR}(X'')$
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is also determined by ramification data (???).
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Assume now that $X \to Y$ is not \'{e}tale. Analogously as in the previous case, Lemma~\ref{lem:TiM_isomorphism_hypoelementary} and proof of Theorem~\ref{thm:cyclic_de_rham}
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yield an isomorphism of $k[C]$-modules:
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%
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\begin{equation} \label{eqn:TiM=T1M_chi}
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T^{i+1} \mc M \cong (T^1 \mc M)^{\chi^{-i}}
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\end{equation}
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%
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for $i \le p^n - p^{n-1}$. Observe that $\mc T^i M$ has the filtration $\mc M^{(pi)} \supset \mc M^{(pi - 1)} \supset \ldots \supset \mc M^{(pi - p)}$ with subquotients $T^{pi} \mc M, \ldots, T^{pi - p + 1} \mc M$.
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Thus, since the category of $k[C]$-modules is semisimple, for $i \le p^n - p^{n-1}$:
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%
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\begin{align*}
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\mc T^i \mc M &\cong T^{pi - p + 1} \mc M \oplus \ldots \oplus T^{pi} \mc M\\
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&\cong T^1 \mc M \oplus (T^1 \mc M)^{\chi^{-1}} \oplus \ldots \oplus
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(T^1 \mc M)^{\chi^{-p}}.
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\end{align*}
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%
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By induction assumption, the $k[C]$-module structure of $\mc T^i \mc M$ is uniquely determined by the ramification data. Thus, by Lemma~\ref{lem:N+Nchi+...} for $N := T^1 \mc M$ and by~\eqref{eqn:TiM=T1M_chi} the $k[C]$-structure of the modules $T^i \mc M$ is uniquely determined by the ramification data for $i \le p^n - p^{n-1}$.
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By similar reasoning, $\tr_{X/X'}$ yields an isomorphism:
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%
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\[
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T^{i + p^n - p^{n-1}} \mc M \cong (\mc T^i \mc M'')^{\chi^{-1??}}.
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\]
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%
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Thus, by induction hypothesis for $\mc M''$, the $k[C]$-structure of $T^{i + p^n - p^{n-1}} \mc M$
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is determined by ramification data as well.
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\end{proof}
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\section{Proof of Main Theorem}
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%
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(Conlon induction ???) (algebraic closure ???)
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\bibliography{bibliografia}
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\end{document} |