Zadanie3
Encode wygląda okej
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65909526af
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65
Zadanie3
65
Zadanie3
@ -1,11 +1,43 @@
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from sys import argv
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def toString(binaryString):
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return "".join([chr(int(binaryString[i:i+8],2)) for i in range(0,len(binaryString),8)])
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def toBinary(string):
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return "".join([format(ord(char),'#010b')[2:] for char in string])
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def binnahex(var):
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all = {"0000": "0",
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"0001": "1",
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"0010": "2",
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"0011": "3",
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"0100": "4",
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"0101": "5",
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"0110": "6",
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"0111": "7",
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"1000": "8",
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"1001": "9",
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"1010": "A",
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"1011": "B",
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"1100": "C",
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"1101": "D",
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"1110": "E",
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"1111": "F"
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}
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i = 0
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output = ""
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while (len(var) % 4 != 0):
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var = "0" + var
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while (i < len(var)):
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output = output + all[var[i:i + 4]]
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i = i + 4
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output = output.lstrip("0")
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output = "0" if len(output) == 0 else output
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return output
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def toString(binaryString):
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return "".join([chr(int(binaryString[i:i+8],2)) for i in range(0,len(binaryString),8)])
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#XOR
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def xor(a, b):
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@ -73,20 +105,25 @@ def decode(message_final,poly16):
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def encode(message, poly16):
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#konwersja z ascii do binarnego
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aa=toBinary(message)
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a=toString(aa)
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l_poly16 = len(poly16)
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obroc = list(aa)
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for i in range(l_poly16 - 1):
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if obroc[i] == "0":
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obroc[i] = "1"
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elif obroc[i] == '1':
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obroc[i] = "0"
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aa = "".join(obroc)
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# Dodajemy n-1 "0" do wiadomosci
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appended_message = aa + '0'*(l_poly16-1)
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appended_message = aa + '0'*(l_poly16-1)
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remainder = divide(appended_message, poly16)
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message_final = aa + remainder
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print("binarnie calosc : ", message_final)
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#konwersja z binarnego do ascii
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ab=toString(message_final)
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print("w ascii : ", ab)
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print("sprawdzenie : ")
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decode(message_final, poly16)
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ab=binnahex(remainder)
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message_final = a + ab
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print("calosc : ", message_final)
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print("crc : ", ab)
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