Rozwiązanie zadania "Ilorazy pierścienia wielomianów" #35
42
main.py
42
main.py
@ -1,4 +1,6 @@
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import itertools
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import ast
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import sys
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class Poly:
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@ -313,39 +315,23 @@ class PolyIntField:
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def __str__(self):
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str_form = "[\n\t"
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str_form += str(self.invertibles()) + ",\n\t"
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str_form += str(self.zero_divisors()) + ",\n\t"
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str_form += str(self.nilpotents()) + ",\n\t"
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str_form += str(self.idempotents()) + "\n"
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str_form += str(self.invertibles()) + ", # odwracalne\n\t"
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str_form += str(self.zero_divisors()) + ", # dzielniki zera\n\t"
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str_form += str(self.nilpotents()) + ", # nilpotenty\n\t"
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str_form += str(self.idempotents()) + " # idempotenty\n"
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str_form += "]\n"
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return str_form
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if __name__ == "__main__":
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# print(phi(36))
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# a = Poly(5, [1])
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# b = Poly(5, [3, 5])
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# # print(a == )
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# p = Poly(2, [1, 1, 1])
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# c = Poly(2, [1, 1])
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# d = Poly(2, [1])
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# print(c * Poly(2, [0, 1]) % p)
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# print(d)
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# print((c * Poly(2, [0, 1]) % p) == d)
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# pf = PolyIntField(2, [1, 1, 1])
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# print(pf.invertibles())
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# a = pf.invertibles()
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# for i in a:
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# print(i)
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if len(sys.argv) < 3:
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print("Niepoprawny input")
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exit(1)
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# a = Poly(5, [1, 1])
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# print(a.elements == {"x1": 1, "x0": 1})
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# [[1], [2], [0, 1], [0, 2], [0, 0, 1], [1, 0, 1], [2, 1, 1], [2, 2, 1], [0, 0, 2], [2, 0, 2], [1, 1, 2], [1, 2, 2]], # odwracalne
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# [ ],
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if sys.argv[1].find(",") != -1:
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print(f"Proszę użyć spacji, nie przecinków: '{sys.argv[1]}'")
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exit(1)
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# [[0, 0, 1], [0, 0, 2], [0, 1], [0, 1, 1], [0, 1, 2], [0, 2], [0, 2, 1], [0, 2, 2], [1], [1, 0, 1], [1, 0, 2], [1, 1], [1, 1, 1], [1, 1, 2], [1, 2], [1, 2, 1], [1, 2, 2], [2], [2, 0, 1], [2, 0, 2], [2, 1], [2, 1, 1], [2, 1, 2], [2, 2], [2, 2, 1], [2, 2, 2]
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d = [[1], [2], [0, 1], [0, 2], [0, 0, 1], [1, 0, 1], [2, 1, 1], [2, 2, 1], [0, 0, 2], [2, 0, 2], [1, 1, 2], [1, 2, 2]]
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print(len(d))
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poly_field = PolyIntField(3, [1, 1, 2, 2])
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print(poly_field)
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field = PolyIntField(int(sys.argv[1]), ast.literal_eval(sys.argv[2]))
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print(field)
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