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2 Commits

Author SHA1 Message Date
Paweł Skórzewski
fa504b4782 Zadanie 10 2023-05-25 10:22:21 +02:00
Paweł Skórzewski
39ccd55544 Poprawki do wykładu 11 2023-05-25 10:22:09 +02:00
2 changed files with 308 additions and 16 deletions

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@ -1,7 +1,6 @@
{ {
"cells": [ "cells": [
{ {
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"cell_type": "markdown", "cell_type": "markdown",
"metadata": { "metadata": {
"slideshow": { "slideshow": {
@ -26,7 +25,6 @@
] ]
}, },
{ {
"attachments": {},
"cell_type": "markdown", "cell_type": "markdown",
"metadata": { "metadata": {
"slideshow": { "slideshow": {
@ -254,18 +252,6 @@
"$$ f(x_1, x_2) = x_1 \\cdot x_2 \\qquad \\to \\qquad \\frac{\\partial f}{\\partial x_1} = x_2, \\quad \\frac{\\partial f}{\\partial x_2} = x_1, \\quad \\nabla f = (x_2, x_1) $$ " "$$ f(x_1, x_2) = x_1 \\cdot x_2 \\qquad \\to \\qquad \\frac{\\partial f}{\\partial x_1} = x_2, \\quad \\frac{\\partial f}{\\partial x_2} = x_1, \\quad \\nabla f = (x_2, x_1) $$ "
] ]
}, },
{
"cell_type": "markdown",
"metadata": {
"slideshow": {
"slide_type": "subslide"
}
},
"source": [
"$$ f(x_1, x_2) = \\max(x_1, x_2) \\hskip{12em} \\\\\n",
"\\to \\qquad \\frac{\\partial f}{\\partial x_1} = \\mathbb{1}_{x_1 \\geq x_2}, \\quad \\frac{\\partial f}{\\partial x_2} = \\mathbb{1}_{x_2 \\geq x_1}, \\quad \\nabla f = (\\mathbb{1}_{x_1 \\geq x_2}, \\mathbb{1}_{x_2 \\geq x_1}) $$ "
]
},
{ {
"cell_type": "markdown", "cell_type": "markdown",
"metadata": { "metadata": {
@ -559,7 +545,6 @@
] ]
}, },
{ {
"attachments": {},
"cell_type": "markdown", "cell_type": "markdown",
"metadata": { "metadata": {
"slideshow": { "slideshow": {
@ -833,7 +818,6 @@
] ]
}, },
{ {
"attachments": {},
"cell_type": "markdown", "cell_type": "markdown",
"metadata": { "metadata": {
"slideshow": { "slideshow": {