2017-11-16 17:33:49 +01:00
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Spanish:
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========
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2017-11-27 21:15:35 +01:00
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2017-11-16 17:33:49 +01:00
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#01:
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2017-11-21 13:51:35 +01:00
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Perfect
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2017-11-16 17:33:49 +01:00
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2017-11-27 21:15:35 +01:00
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2017-11-16 17:33:49 +01:00
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#02:
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2017-11-21 13:51:35 +01:00
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Perfect
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2017-11-16 17:33:49 +01:00
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2017-11-21 17:07:58 +01:00
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2017-11-21 15:52:20 +01:00
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#03: [??]
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2017-12-05 23:35:16 +01:00
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¿Preguntar si esta bién? Las || barras (una o dos)
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2017-11-16 17:33:49 +01:00
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2017-11-27 21:15:35 +01:00
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2017-11-16 17:33:49 +01:00
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#04:
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2017-11-21 13:51:35 +01:00
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Perfect
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2017-11-16 17:33:49 +01:00
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2017-11-21 17:07:58 +01:00
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2017-11-27 21:13:58 +01:00
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#05:
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Perfect.
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Revisado por profesor y corregido.
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2017-11-21 16:16:59 +01:00
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2017-11-21 17:07:58 +01:00
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2017-11-16 17:33:49 +01:00
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#06:
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2017-11-27 21:15:35 +01:00
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Perfect.
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Revisado por profesor. Me dijo que estab bien.
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Preguntar si son necesarios más ejemplos por si acaso.
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2017-11-16 17:33:49 +01:00
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2017-11-21 17:07:58 +01:00
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#07: [??]
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2017-11-16 18:23:55 +01:00
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2017-11-21 17:18:58 +01:00
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Que hay que hacer aqui:
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Resolver la ecuacion??
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No se como hacerlo.
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2017-11-27 21:16:54 +01:00
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Es una derivada.
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contrib_one = True
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2017-11-21 17:18:58 +01:00
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2017-11-16 18:23:55 +01:00
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+ Solve equation \frac{d^2 u}{dx^2}-x\frac{du}{dx}+u=0
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2017-11-27 21:42:32 +01:00
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d^(2) * u d * u
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F: ------------- -x * ---------- + u = 0
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dx^2 d * x
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2017-12-05 23:35:16 +01:00
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2017-12-09 23:33:42 +01:00
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---------------------------------------->>>>>>> ¡¡Quedo en pasarme la solución!!
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2017-11-27 21:42:32 +01:00
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2017-11-27 21:15:35 +01:00
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2017-11-16 17:33:49 +01:00
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#08
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2017-11-27 21:17:43 +01:00
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Perfect.
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Revisado por profesor.
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2017-11-16 17:33:49 +01:00
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2017-11-27 21:15:35 +01:00
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2017-12-09 23:33:42 +01:00
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#09: [??]
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2017-11-16 17:33:49 +01:00
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2017-12-10 01:09:49 +01:00
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¿Es correcto?
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2017-11-16 17:33:49 +01:00
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2017-12-09 23:33:42 +01:00
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2017-11-16 17:33:49 +01:00
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#10
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2017-12-10 01:09:49 +01:00
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¿Es correcto? Sobre todo el teorema.
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2017-11-16 17:33:49 +01:00
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2017-12-09 23:33:42 +01:00
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2017-11-16 17:33:49 +01:00
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#11
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#12
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