DALGLI0/Zadanie3

def toBinary(string):
    return "".join([format(ord(char),'#010b')[2:] for char in string])

def toString(binaryString):
    return "".join([chr(int(binaryString[i:i+8],2)) for i in range(0,len(binaryString),8)])

#XOR
def xor(a, b):
 
    # init
    result = []
 
    # porownuje znaki
    for i in range(1, len(b)):
        if a[i] == b[i]:
            result.append('0')
        else:
            result.append('1')
 
    return ''.join(result)
 
 
# dzielenie modulo 2
def divide(message, poly16):
 
    # Ilosc bitow dla operacji XOR 'na raz'
    step = len(poly16)
 
    # podzial krok po kroku
    temp = message[0 : step]
 
    while step < len(message):
 
        if temp[0] == '1':
 
            temp = xor(poly16, temp) + message[step]
 
        else:   
            # jezeli 1 bit po lewej == 0
            temp = xor('0'*step, temp) + message[step]
 
        # kolejny krok
        step += 1
 
    if temp[0] == '1':
        temp = xor(poly16, temp)
    else:
        temp = xor('0'*step, temp)
 
    check = temp
    return check


def decode(message_final,poly16):

    l_poly16 = len(poly16)
    appended_message2 = message_final
    remainder = divide(appended_message2, poly16)
    #sprawdzenie kazdego bitu
    for i in range(0, len(remainder)):
            if '1' not in remainder:
                print("true ")
            elif '1' in remainder:
                print("false ")

 
def encode(message, poly16):
    #konwersja z ascii do binarnego
    aa=toBinary(message)

    l_poly16 = len(poly16)
 
    # Dodaj n-1 "0" do wiadomosci
    appended_message = aa + '0'*(l_poly16-1)
    remainder = divide(appended_message, poly16)
 
    message_final = aa + remainder
    print("binarnie calosc : ", message_final)
    #konwersja z ascii do binarnego
    ab=toString(message_final)
    print("w ascii : ", ab)
    print("sprawdzenie : ")
    decode(message_final, poly16)


    
poly16 = "10001000000100001"
print("podaj wiadomosc do zakodowania : ")
message = str(raw_input())
encode(message, poly16)