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rozwiazanie zad 2

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s407531 2018-05-13 09:53:19 +02:00
parent f64e91b82f
commit 46c569c67b
1 changed files with 9 additions and 1 deletions
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labs02/task03.py
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@ -11,9 +11,17 @@ litery. (OOV = out of vocabulary) (W pythonie istnieje struktura danych tak
jak 'set', która przechowuje elementy bez powtórzeń.)
"""
from sets import Set
def oov(text, vocab):
pass
rozdzielenie=text.split(' ')
slowo=set()
slowo=(slowo for slowo in rozdzielenie if slowo not in vocab)
return slowo