29 lines
1.2 KiB
Plaintext
29 lines
1.2 KiB
Plaintext
|
Deterministic automaton III
|
||
|
===========================
|
||
|
|
||
|
Read a description of a finite-state automaton in the AT&T format
|
||
|
(without weights) from the standard input. Then, read strings from the
|
||
|
file whose name was given as the first argument. If a string is
|
||
|
accepted by the automated, write YES, a space and the string on the
|
||
|
standard output, otherwise — write NO, a space and the string.
|
||
|
|
||
|
If there is a non-determinism in the automaton, the first transition should be chosen.
|
||
|
|
||
|
The automaton can contain epsilon transitions ("<eps>" instead of a
|
||
|
character). They should be interpreted as follows: an epsilon
|
||
|
transition can be used (without "eating" a character from the input),
|
||
|
if there is no other transition applicable. You can assume that there
|
||
|
is at most one epsilon transition from a given state and that there
|
||
|
are no cycles with epsilon transition.
|
||
|
|
||
|
Your program does not have to check whether the description is correct
|
||
|
and whether the automaton is deterministic. You can assume that the
|
||
|
automaton does not contain epsilon transitions.
|
||
|
|
||
|
NOTE: Task only for students whose student index number ("numer
|
||
|
indeksu") is divisable by 3 with a remainder of 2
|
||
|
|
||
|
POINTS: 8
|
||
|
DEADLINE: 2019-11-14 23:59
|
||
|
REMAINDER: 2/3
|