125 lines
4.3 KiB
Python
125 lines
4.3 KiB
Python
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"""Routine to "compile" a .py file to a .pyc (or .pyo) file.
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This module has intimate knowledge of the format of .pyc files.
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"""
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import _py_compile
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import os
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import sys
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import traceback
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__all__ = ["compile", "main", "PyCompileError"]
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class PyCompileError(Exception):
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"""Exception raised when an error occurs while attempting to
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compile the file.
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To raise this exception, use
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raise PyCompileError(exc_type,exc_value,file[,msg])
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where
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exc_type: exception type to be used in error message
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type name can be accesses as class variable
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'exc_type_name'
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exc_value: exception value to be used in error message
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can be accesses as class variable 'exc_value'
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file: name of file being compiled to be used in error message
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can be accesses as class variable 'file'
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msg: string message to be written as error message
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If no value is given, a default exception message will be given,
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consistent with 'standard' py_compile output.
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message (or default) can be accesses as class variable 'msg'
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"""
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def __init__(self, exc_type, exc_value, file, msg=''):
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exc_type_name = exc_type.__name__
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if exc_type is SyntaxError:
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tbtext = ''.join(traceback.format_exception_only(exc_type, exc_value))
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errmsg = tbtext.replace('File "<string>"', 'File "%s"' % file)
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else:
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errmsg = "Sorry: %s: %s" % (exc_type_name,exc_value)
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Exception.__init__(self,msg or errmsg,exc_type_name,exc_value,file)
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self.exc_type_name = exc_type_name
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self.exc_value = exc_value
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self.file = file
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self.msg = msg or errmsg
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def __str__(self):
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return self.msg
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def compile(file, cfile=None, dfile=None, doraise=False):
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"""Byte-compile one Python source file to Python bytecode.
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Arguments:
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file: source filename
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cfile: target filename; defaults to source with 'c' or 'o' appended
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('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
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dfile: purported filename; defaults to source (this is the filename
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that will show up in error messages)
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doraise: flag indicating whether or not an exception should be
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raised when a compile error is found. If an exception
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occurs and this flag is set to False, a string
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indicating the nature of the exception will be printed,
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and the function will return to the caller. If an
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exception occurs and this flag is set to True, a
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PyCompileError exception will be raised.
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Note that it isn't necessary to byte-compile Python modules for
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execution efficiency -- Python itself byte-compiles a module when
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it is loaded, and if it can, writes out the bytecode to the
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corresponding .pyc (or .pyo) file.
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However, if a Python installation is shared between users, it is a
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good idea to byte-compile all modules upon installation, since
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other users may not be able to write in the source directories,
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and thus they won't be able to write the .pyc/.pyo file, and then
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they would be byte-compiling every module each time it is loaded.
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This can slow down program start-up considerably.
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See compileall.py for a script/module that uses this module to
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byte-compile all installed files (or all files in selected
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directories).
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"""
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try:
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_py_compile.compile(file, cfile, dfile)
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except Exception,err:
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py_exc = PyCompileError(err.__class__,err.args,dfile or file)
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if doraise:
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raise py_exc
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else:
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sys.stderr.write(py_exc.msg + '\n')
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return
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def main(args=None):
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"""Compile several source files.
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The files named in 'args' (or on the command line, if 'args' is
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not specified) are compiled and the resulting bytecode is cached
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in the normal manner. This function does not search a directory
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structure to locate source files; it only compiles files named
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explicitly.
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"""
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if args is None:
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args = sys.argv[1:]
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for filename in args:
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try:
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compile(filename, doraise=True)
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except PyCompileError,err:
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sys.stderr.write(err.msg)
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if __name__ == "__main__":
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main()
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