labs02 ready

labs02/task02.py

@@ -17,13 +17,6 @@ def days_in_year(days):
     else:
         return 365
 
-    # To determine whether a year is a leap year, follow these steps: 
-    #     If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
-    #     If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
-    #     If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
-    #     The year is a leap year (it has 366 days).
-    #     The year is not a leap year (it has 365
-
 def tests(f):
     inputs = [[2015], [2012], [1900], [2400], [1977]]
     outputs = [365, 366, 365, 366, 365]

labs02/task03.py

@@ -13,8 +13,7 @@ jak 'set', która przechowuje elementy bez powtórzeń.)
 
 
 def oov(text, vocab):
-    words = text.lower().split()
-    return (set(words) - set(vocab))
+    return (set(text.lower().split()) - set(vocab))
 
 def tests(f):
     inputs = [("this is a string , which i will use for string testing",

labs02/task05.py

@@ -10,10 +10,7 @@ np. odległość pomiędzy punktami (0, 0, 0) i (3, 4, 0) jest równa 5.
 """
 
 def euclidean_distance(x, y):
-    dist = 0
-    for i, j in zip(x, y):
-        dist += (i-j) ** 2
-    return m.sqrt(dist)
+    return m.sqrt(sum((i-j)**2 for i, j in zip(x, y)))
 
 def tests(f):
     inputs = [[(2.3, 4.3, -7.5), (2.3, 8.5, -7.5)]]

labs02/task09.py

@@ -9,8 +9,11 @@ Np. leet('leet') powinno zwrócić '1337'.
 
 
 def leet_speak(text):
-    pass
-
+    words_dict = { 'e': '3', 'l': '1', 'o': '0', 't': '7' }
+    for letter in text:
+        if letter in words_dict:
+            text = text.replace(letter, words_dict[letter])
+    return text
 
 def tests(f):
     inputs = [['leet'], ['do not want']]

labs02/task10.py

@@ -9,8 +9,13 @@ na wielką. Np. pokemon_speak('pokemon') powinno zwrócić 'PoKeMoN'.
 
 
 def pokemon_speak(text):
-    pass
-
+    result = []
+    for i in range(len(text)):
+        if i % 2 == 0:
+            result.append(text[i].upper())
+        else:
+            result.append(text[i])
+    return ''.join(result)
 
 def tests(f):
     inputs = [['pokemon'], ['do not want'], ['POKEMON']]

labs02/task11.py

@@ -11,7 +11,6 @@ Oba napisy będą składać się wyłacznie z małych liter.
 def common_chars(string1, string2):
     return sorted(set(string1.replace(' ', '')) & set(string2.replace(' ', '')))
 
-
 def tests(f):
     inputs = [["this is a string", "ala ma kota"]]
     outputs = [['a', 't']]

labs02/test_task.py

@@ -6,7 +6,7 @@ def suma(a, b):
     """
     Napisz funkcję, która zwraca sumę elementów.
     """
-    return 0
+    return a + b
 
 def tests(f):
     inputs = [(2, 3), (0, 0), (1, 1)]