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talestex.pdf
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69
talestex.pdf
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\documentclass[]{beamer}
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\usepackage{tikz}
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\usepackage[polish]{babel}
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\usepackage[utf8]{inputenc}
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\usepackage[T1]{fontenc}
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\usetheme{EastLansing}
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\begin{document}
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\author{Aleksandra Jonas}
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\title{Twierdzenie Telesa}
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\institute{Adam Mickiewicz University}
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\date{21 stycznia 2019}
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\begin{frame}[plain]
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\maketitle
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\end{frame}
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\begin{frame}
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\begin{center}
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\frametitle{Tales}
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\begin{figure}
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\includegraphics[scale=0.75]{j:/Downloads/tales}
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\end{figure}
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\end{center}
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\end{frame}
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\begin{frame}[plain]
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\begin{center}
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\begin{tikzpicture}[]
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\draw
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[black, dotted] (-2,0)--(4,0)--(3,3)--(2,6);
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\draw
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[pink] (1,-1)--(5,3)
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[pink] (-1,-1)--(5,5)
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[red, very thick]
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(4,0) node [below, right]{A}
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(2,0) node [below]{B}
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(0,0) node [below] {C}
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(3.5,1.5) node [right]{D}
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(3,3) node [right]{E}
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[black, very thick]
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(5,2) node [above] {k}
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(5,4) node [above, left] {m}
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(-1,4) node [above] {k II m}
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[pink]
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(4,0) node {•}
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(2,0) node {•}
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(3,3) node {•}
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(3.5,1.5) node {•}
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(0,0) node {•};
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\end{tikzpicture}
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\end{center}
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\end{frame}
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\begin{frame}
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\begin{itemize}
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\item Jeżeli ramiona kąta przecięte są prostymi równoległymi, to: \pause
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\item $\dfrac{|AD|}{|AB|}=$\pause $\dfrac{|BC|}{|DE|}$
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\end{itemize}
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\end{frame}
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\begin{frame}
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\begin{center}
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Dziękuję za uwagę!
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\end{center}
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\end{frame}
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\end{document}
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