Logic-Formulae-Validator-dla-ubogich/program.py

import sys
import subprocess

class AbstractInterpreter:
    def __init__(self):
        pass
    def isValid(self,formula:str)->bool:
        raise NotImplementedError
class SimpleInterpreter(AbstractInterpreter):
    def __init__(self):
        pass
    def isValid(self,formula)->bool:
       
        variables = {}
        f=[]
        def isBlacklisted(char):
            return char in ['\n', '\t', ' ']
        def isSign(char):
            logic_signs = ['=', '>', '&', '|', '!', '(', ')']
            return char in logic_signs
        def isParentice(char):
            return char in ('(', ')')
        def isVariable(char):
            return  not isSign(char) 
        def isNegation(char):
            return char == '!'
        #print(vars(formula))
        for i,char in enumerate(formula.s):
            if isBlacklisted(char): return False
           
            prev = formula.s[i-1] if i>0 else None #None, gdy jesteśmy na pierwszym znaku
            if (char=='(' and isVariable(prev) and prev is not None): #a(b|c)
                return False
            if isSign(char):
                if (not isNegation(char)):
                    if isSign(prev) and not isNegation(prev): # tylko negacje mogą się powtarzać po innym znaku
                        return False
                else:
                    if isVariable(prev) and prev is not None: # obrona przed a!>b
                        return False
            else:
                 #if current char is a variable
                 if isVariable(prev) and prev is not None: #Obrona abc>d
                     print("previous is also a variable");
                     return False
        return True
class RegexInterpreter(AbstractInterpreter):
    def __init__(self):
        #check if grep is available
        import subprocess
       # r=subprocess.run("grep")
       
    def isValid(self,f)->bool:
        
        formula = "({0})".format(f.s.replace("!", "\\!"))

        make_reg = lambda formula,pattern: 'echo "{0}" | grep -P "{1}"'.format(formula,pattern)
        def check_assertion(formula, pattern):
            cmd = make_reg(formula,pattern)
            print("EXECUTING... ",cmd)
            result = subprocess.run([cmd], shell=True, stdout=subprocess.PIPE)
            return len(result.stdout)>0
       
        cmd =make_reg(formula,'^(\((?:[^()]++|(?1))*\))$')
        print("EXECUTING... ",cmd)
       
        result = subprocess.run([cmd], shell=True, stdout=subprocess.PIPE)
        return None
        isValid = len(result.stdout)>0
        if not isValid: return False

        #assertions
        assertions = ['(?:[>|&|\|=][\(\)]*){2,}','\((?:[>|&|\|=][\(\)]*)','[a-z]{2,}','\((?:[>|&|\|=|!])?\)']
        for assertion in assertions:
            if not check_assertion(formula,assertion):
                return False

        return True
        # (?:[>|&|\|=][\(\)]*){2,} - czy powtarzają się jakieś operatory obok siebie?


        # echo "formuła" | grep -P "regex"  - to jeżeli coś zwróci to znaczy, że mamy dopasowanie
        #najpierw sprawdzamy, czy parentices są ok
        #^(\((?:[^()]++|(?1))*\))$ - powinno zwrócić cały nasz string
        #potem sprawdzamy czy dopasuje cokolwiek co może być nie tak
        
        #  \((?:[>|&|\|=][\(\)]*) - (>b)
        # [a-z]{2,} - czy powtarzają się jakieś lierki obok siebie?
        # \((?:[>|&|\|=|!])?\) - czy istnieją puste nawiasy, bądź nawiasy z samym operatorem?
class ProperInterpreter(AbstractInterpreter):
    class Expression:
        def __init__(self,operator,left,right):
            self.right=right
            self.left = left
            self.operator = operator
        
    def __init__(self):
        pass
    def isValid(self,formula)->bool:
        try:
            self.parse(formula.s)
        except Exception as e:
            print(e)
            return False
        else:
            return True
    def check_simple_formula(self,simple_formula:str)->bool:
        #używamy SimpleInterpretera
        n = SimpleInterpreter()
        return Formula(simple_formula,n).isValid()
    def parse(self,formula:str):
        #przypisywanie głębi do każdego znaku
        if len(formula)==0:
            # print("Empty subformula")
             return None
        x=[0 for u in formula]
        current_depth=0
        for i,char in enumerate(formula):
            if current_depth<0:
                break
            if char == '(':
                current_depth+=1
                x[i] = current_depth
            elif char == ')':
                x[i] = current_depth
                current_depth-=1
            else:
                x[i] = current_depth

     
        if current_depth!=0:
             raise Exception("Nawiasy źle umieszczone w podformule: {0}".format(formula))
           
        #print(formula)
        
        min_depth = min(x)
        
        slice_point = 0
        #czy formuła jest prosta?
        is_simple = True
        for i in x:
            if i != x[0]:
                is_simple=False;
                break    
        #Szukanie najbardziej znaczącego spójnika
        for i,char in enumerate(formula):
            if char in ('>', '&', '|', '=') and x[i] == min_depth:
                slice_point = i
                break
        if is_simple:
           # print(formula, " is simple")
            if not self.check_simple_formula(formula):
                raise Exception("Błąd na poziomie formuły bez zagnieżdzeń: {0}".format(formula))
                return False
        
        else:
            s=0
            e=len(formula)
            if min_depth>0:
               # print("There are useless parentices... Deleting")
                s=1
                e=-1
           # print("Slice point: ", slice_point)
           # print("min depth: ", min_depth)
            if (s==slice_point):
                #print("Nie ma spójnika - formuła jest jednak prosta")
                if not self.check_simple_formula(formula):
                    raise Exception("Błąd na poziomie formuły bez zagnieżdzeń: {0}".format(formula))
                    return False
            self.parse(formula[s:slice_point])
            self.parse(formula[slice_point+1:e])
class Formula:
    def __init__(self, formula_string:str, interpreter:AbstractInterpreter=None):
        self.s = formula_string
        self.__i = interpreter
        
    def isValid(self, interpreter=None)->bool:
        i = self.__i if interpreter is None else interpreter
        return i.isValid(self)

if len(sys.argv) > 1 :
    i = ProperInterpreter()
    if '-g' in sys.argv: 
        i = RegexInterpreter()
    print(sys.argv)

    if '-f' in sys.argv:
        #open from file
        print("opening from file")
        g = open(sys.argv[sys.argv.index('-f')+1], 'r')
        u = g.readlines()
        for l in u:
            print(Formula(l,i).isValid())
    else:
        print(Formula( sys.argv[1] if sys.argv[1] != '-g' else sys.argv[2],i).isValid())
   
else:
    print("help?")