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Task03 completed - passed
# commented lower() method.
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@ -11,9 +11,15 @@ litery. (OOV = out of vocabulary) (W pythonie istnieje struktura danych tak
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jak 'set', która przechowuje elementy bez powtórzeń.)
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"""
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def oov(text,vocab):
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pass
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# text = text.lower()
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# vocab = vocab.lower()
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wynik = []
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text = set(text.split())
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for i in text:
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if i not in vocab:
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wynik.append(i)
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return wynik
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