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Poprawki do wykładu 11
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@ -1,7 +1,6 @@
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{
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"cells": [
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{
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"attachments": {},
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"cell_type": "markdown",
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"metadata": {
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"slideshow": {
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@ -26,7 +25,6 @@
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]
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},
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{
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"attachments": {},
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"cell_type": "markdown",
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"metadata": {
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"slideshow": {
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@ -254,18 +252,6 @@
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"$$ f(x_1, x_2) = x_1 \\cdot x_2 \\qquad \\to \\qquad \\frac{\\partial f}{\\partial x_1} = x_2, \\quad \\frac{\\partial f}{\\partial x_2} = x_1, \\quad \\nabla f = (x_2, x_1) $$ "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {
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"slideshow": {
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"slide_type": "subslide"
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}
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},
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"source": [
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"$$ f(x_1, x_2) = \\max(x_1, x_2) \\hskip{12em} \\\\\n",
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"\\to \\qquad \\frac{\\partial f}{\\partial x_1} = \\mathbb{1}_{x_1 \\geq x_2}, \\quad \\frac{\\partial f}{\\partial x_2} = \\mathbb{1}_{x_2 \\geq x_1}, \\quad \\nabla f = (\\mathbb{1}_{x_1 \\geq x_2}, \\mathbb{1}_{x_2 \\geq x_1}) $$ "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {
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]
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},
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{
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"attachments": {},
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"cell_type": "markdown",
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"metadata": {
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"slideshow": {
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@ -833,7 +818,6 @@
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]
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},
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{
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"attachments": {},
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"cell_type": "markdown",
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"metadata": {
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"slideshow": {
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