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Task E

This commit is contained in:
HOME-VM-TOSCHOOL 2024-02-18 20:49:26 +01:00
parent d6a99fbae7
commit 9f9d0ec887
5 changed files with 165 additions and 1 deletions
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41
TaskE00/run.py Normal file
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import re
FILE_NAME = "test"
MODE = "test"
def is_correct(line: str):
looking_pattern = re.compile(r"^-?(0|[1-9]\d*[05])$")
if re.search(looking_pattern, line):
return "yes"
else:
return "no"
if MODE == "test":
with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
text = [line.rstrip() for line in file.readlines()]
with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
expected = [line.rstrip() for line in file.readlines()]
out: list[str] = []
for line in text:
out.append(is_correct(line))
for ind, found in enumerate(out):
if found == expected[ind]:
print(found)
else:
print("ERROR")
elif MODE == "input":
line = input("Enter a line: ")
# Check if the line is an acronym and print 'yes' or 'no'
if is_correct(line) == "yes":
print("yes")
else:
print("no")

41
TaskE01/run.py Normal file
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import re
FILE_NAME = "test"
MODE = "test"
def is_correct(line: str):
looking_pattern = re.compile(r"^\d*(00|25|50|75)$")
if re.search(looking_pattern, line):
return "yes"
else:
return "no"
if MODE == "test":
with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
text = [line.rstrip() for line in file.readlines()]
with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
expected = [line.rstrip() for line in file.readlines()]
out: list[str] = []
for line in text:
out.append(is_correct(line))
for ind, found in enumerate(out):
if found == expected[ind]:
print(found)
else:
print(f"ERROR: expected - {expected[ind]}, found - {found}")
elif MODE == "input":
line = input("Enter a line: ")
# Check if the line is an acronym and print 'yes' or 'no'
if is_correct(line) == "yes":
print("yes")
else:
print("no")

2
TaskE03/description.txt
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@ -22,7 +22,7 @@ Jeśli napis spełnia tak określony warunek, należy wypisać na
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
For each string check, if the string is NIP number written in
xxx-xxx-xx-xx bądź xxx-xx-xx-xxx format. You don't need to consider a checksum.
xxx-xxx-xx-xx or xxx-xx-xx-xxx format. You don't need to consider a checksum.
If the string fulfills the condition, you should print 'yes' on the
standard output and 'no' otherwise.

41
TaskE03/run.py Normal file
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import re
FILE_NAME = "test"
MODE = "test"
def is_correct(line: str):
looking_pattern = re.compile(r"^\d{3}-\d{3}-\d{2}-\d{2}$|^\d{3}-\d{2}-\d{2}-\d{3}$")
if re.search(looking_pattern, line):
return "yes"
else:
return "no"
if MODE == "test":
with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
text = [line.rstrip() for line in file.readlines()]
with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
expected = [line.rstrip() for line in file.readlines()]
out: list[str] = []
for line in text:
out.append(is_correct(line))
for ind, found in enumerate(out):
if found == expected[ind]:
print(found)
else:
print(f"ERROR: expected - {expected[ind]}, found - {found}")
elif MODE == "input":
line = input("Enter a line: ")
# Check if the line is an acronym and print 'yes' or 'no'
if is_correct(line) == "yes":
print("yes")
else:
print("no")

41
TaskE04/run.py Normal file
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@ -0,0 +1,41 @@
import re
FILE_NAME = "test"
MODE = "test"
def is_correct(line: str):
looking_pattern = re.compile(r"^((555-\d{3}-\d{3})|(555 \d{3} \d{3}))$")
if re.search(looking_pattern, line):
return "yes"
else:
return "no"
if MODE == "test":
with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
text = [line.rstrip() for line in file.readlines()]
with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
expected = [line.rstrip() for line in file.readlines()]
out: list[str] = []
for line in text:
out.append(is_correct(line))
for ind, found in enumerate(out):
if found == expected[ind]:
print(found)
else:
print(f"ERROR: expected - {expected[ind]}, found - {found}")
elif MODE == "input":
line = input("Enter a line: ")
# Check if the line is an acronym and print 'yes' or 'no'
if is_correct(line) == "yes":
print("yes")
else:
print("no")