Task E
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TaskE00/run.py
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41
TaskE00/run.py
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import re
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FILE_NAME = "test"
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MODE = "test"
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def is_correct(line: str):
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looking_pattern = re.compile(r"^-?(0|[1-9]\d*[05])$")
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if re.search(looking_pattern, line):
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return "yes"
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else:
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return "no"
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if MODE == "test":
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with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
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text = [line.rstrip() for line in file.readlines()]
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with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
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expected = [line.rstrip() for line in file.readlines()]
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out: list[str] = []
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for line in text:
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out.append(is_correct(line))
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for ind, found in enumerate(out):
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if found == expected[ind]:
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print(found)
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else:
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print("ERROR")
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elif MODE == "input":
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line = input("Enter a line: ")
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# Check if the line is an acronym and print 'yes' or 'no'
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if is_correct(line) == "yes":
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print("yes")
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else:
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print("no")
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41
TaskE01/run.py
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41
TaskE01/run.py
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import re
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FILE_NAME = "test"
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MODE = "test"
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def is_correct(line: str):
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looking_pattern = re.compile(r"^\d*(00|25|50|75)$")
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if re.search(looking_pattern, line):
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return "yes"
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else:
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return "no"
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if MODE == "test":
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with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
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text = [line.rstrip() for line in file.readlines()]
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with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
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expected = [line.rstrip() for line in file.readlines()]
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out: list[str] = []
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for line in text:
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out.append(is_correct(line))
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for ind, found in enumerate(out):
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if found == expected[ind]:
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print(found)
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else:
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print(f"ERROR: expected - {expected[ind]}, found - {found}")
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elif MODE == "input":
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line = input("Enter a line: ")
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# Check if the line is an acronym and print 'yes' or 'no'
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if is_correct(line) == "yes":
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print("yes")
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else:
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print("no")
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@ -22,7 +22,7 @@ Jeśli napis spełnia tak określony warunek, należy wypisać na
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standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
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standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
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For each string check, if the string is NIP number written in
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For each string check, if the string is NIP number written in
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xxx-xxx-xx-xx bądź xxx-xx-xx-xxx format. You don't need to consider a checksum.
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xxx-xxx-xx-xx or xxx-xx-xx-xxx format. You don't need to consider a checksum.
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If the string fulfills the condition, you should print 'yes' on the
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If the string fulfills the condition, you should print 'yes' on the
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standard output and 'no' otherwise.
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standard output and 'no' otherwise.
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41
TaskE03/run.py
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41
TaskE03/run.py
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import re
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FILE_NAME = "test"
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MODE = "test"
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def is_correct(line: str):
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looking_pattern = re.compile(r"^\d{3}-\d{3}-\d{2}-\d{2}$|^\d{3}-\d{2}-\d{2}-\d{3}$")
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if re.search(looking_pattern, line):
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return "yes"
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else:
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return "no"
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if MODE == "test":
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with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
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text = [line.rstrip() for line in file.readlines()]
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with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
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expected = [line.rstrip() for line in file.readlines()]
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out: list[str] = []
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for line in text:
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out.append(is_correct(line))
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for ind, found in enumerate(out):
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if found == expected[ind]:
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print(found)
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else:
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print(f"ERROR: expected - {expected[ind]}, found - {found}")
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elif MODE == "input":
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line = input("Enter a line: ")
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# Check if the line is an acronym and print 'yes' or 'no'
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if is_correct(line) == "yes":
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print("yes")
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else:
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print("no")
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41
TaskE04/run.py
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41
TaskE04/run.py
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import re
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FILE_NAME = "test"
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MODE = "test"
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def is_correct(line: str):
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looking_pattern = re.compile(r"^((555-\d{3}-\d{3})|(555 \d{3} \d{3}))$")
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if re.search(looking_pattern, line):
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return "yes"
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else:
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return "no"
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if MODE == "test":
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with open(FILE_NAME + ".in", "r", newline="", encoding="utf8") as file:
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text = [line.rstrip() for line in file.readlines()]
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with open(FILE_NAME + ".exp", "r", newline="", encoding="utf8") as file:
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expected = [line.rstrip() for line in file.readlines()]
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out: list[str] = []
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for line in text:
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out.append(is_correct(line))
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for ind, found in enumerate(out):
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if found == expected[ind]:
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print(found)
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else:
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print(f"ERROR: expected - {expected[ind]}, found - {found}")
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elif MODE == "input":
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line = input("Enter a line: ")
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# Check if the line is an acronym and print 'yes' or 'no'
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if is_correct(line) == "yes":
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print("yes")
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else:
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print("no")
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