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README.md
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## Zajęcia 1 ## Zajęcia 1
Copyright AMU Poznan
Made by multiple people
### Informacje na temat przedmiotu ### Informacje na temat przedmiotu
Prowadzący: Jacek Kałużny Prowadzący: Jacek Kałużny
@ -23,3 +18,347 @@ W ten sposób będziemy aktualizować zadania co zajęcia.
Zadania robimy do końca soboty poprzedzającej zajęcia Zadania robimy do końca soboty poprzedzającej zajęcia
Rozwiązanie zapisujemy w pliku run.py Rozwiązanie zapisujemy w pliku run.py
## Zajęcia 2 Wyrażenia regularne
Dokumentacja wyrażeń regularnych w python3: https://docs.python.org/3/library/re.html
### Podstawowe funkcje
search - zwraca pierwsze dopasowanie w napisie
findall - zwraca listę wszystkich dopasowań (nienakładających się na siebie)
match - zwraca dopasowanie od początku string
To tylko podstawowe funkcje, z których będziemy korzystać. W dokumentacji opisane są wszystkie.
### Obiekt match
```
import re
answer = re.search('na','banan')
print(answer)
print(answer.start())
print(answer.end())
print(answer.group())
answer = re.search('na','kabanos')
print(answer)
type(answer)
if answer:
print(answer.group())
else:
pass
```
### Metaznaki
- [] - zbiór znaków
- . - jakikolwiek znak
- ^ - początek napisu
- $ - koniec napisu
- ? - znak występuje lub nie występuje
- \* - zero albo więcej pojawień się
- \+ - jeden albo więcej pojawień się
- {} - dokładnie tyle pojawień się
- | - lub
- () - grupa
- \ -znak ucieczki
- \d digit
- \D nie digit
- \s whitespace
- \S niewhitespace
### Flagi
Można użyć specjalnych flag, np:
`re.search('ma', 'AlA Ma KoTa', re.IGNORECASE)`.
### Przykłady (objaśnienia na laboratoriach)
Do nauki lepiej użyć pythona w wersji interaktywnej, a najlepiej ipython.
```
import re
text = 'Ala ma kota i hamak, oraz 150 bananów.'
re.search('ma',text)
re.match('ma',text)
re.match('Ala ma',text)
re.findall('ma',text)
re.findall('[mn]a',text)
re.findall('[0-9]',text)
re.findall('[0-9abc]',text)
re.findall('[a-z][a-z]ma[a-z]',text)
re.findall('[a-zA-Z][a-zA-Z]ma[a-zA-z0-9]',text)
re.findall('\d',text)
re.search('[0-9][0-9][0-9]',text)
re.search('[\d][\d][\d]',text)
re.search('\d{2}',text)
re.search('\d{3}',text)
re.search('\d+',text)
re.search('\d+ bananów',text)
re.search('\d* bananów','Ala ma dużo bananów')
re.search('\d* bananów',text)
re.search('ma \d? bananów','Ala ma 5 bananów')
re.search('ma ?\d? bananów','Ala ma bananów')
re.search('ma( \d)? bananów','Ala ma bananów')
re.search('\d+ bananów','Ala ma 10 bananów albo 20 bananów')
re.search('\d+ bananów$','Ala ma 10 bananów albo 20 bananów')
text = 'Ala ma kota i hamak, oraz 150 bananów.'
re.search('\d+ bananów',text)
re.search('\d+\sbananów',text)
re.search('kota . hamak',text)
re.search('kota . hamak','Ala ma kota z hamakiem')
re.search('kota .* hamak','Ala ma kota lub hamak')
re.search('\.',text)
re.search('kota|psa','Ala ma kota lub hamak')
re.findall('kota|psa','Ala ma kota lub psa')
re.search('kota (i|lub) psa','Ala ma kota lub psa')
re.search('mam (kota).*(kota|psa)','Ja mam kota. Ala ma psa.').group(0)
re.search('mam (kota).*(kota|psa)','Ja mam kota. Ala ma psa.').group(1)
re.search('mam (kota).*(kota|psa)','Ja mam kota. Ala ma psa.').group(2)
```
### Przykłady wyrażenia regularne 2 (objaśnienia na laboratoriach)
#### ^
```
re.search('[0-9]+', '123-456-789')
re.search('[^0-9][0-9]+[^0-9]', '123-456-789')
```
#### cudzysłów
'' oraz "" - oznaczają to samo w pythonie
' ala ma psa o imieniu "Burek"'
" ala ma psa o imieniu 'Burek' "
' ala ma psa o imieniu \'Burek\' '
" ala ma psa o imieniu \"Burek\" "
#### multiline string
#### raw string
przy raw string znaki \ traktowane są jako zwykłe znaki \
chociaż nawet w raw string nadal są escapowane (ale wtedy \ pozostają również w stringu bez zmian)
https://docs.python.org/3/reference/lexical_analysis.html
dobra praktyka - wszędzie escapować
```
'\\'
print('\\')
r'\\'
print(r'\\')
print("abcd")
print("ab\cd")
print(r"ab\cd")
print("ab\nd")
print(r"ab\nd")
print("\"")
print(r"\"")
print("\")
print(r"\")
re.search('\\', r'a\bc')
re.search(r'\\', r'a\bc')
re.search('\\\\', r'a\bc')
```
#### RE SUB
```
re.sub(pattern, replacement, string)
re.sub('a','b', 'ala ma kota')
```
#### backreferencje:
```
re.search(r' \d+ \d+', 'ala ma 41 41 kota')
re.search(r' \d+ \d+', 'ala ma 41 123 kota')
re.search(r' (\d+) \1', 'ala ma 41 41 kota')
re.search(r' (\d+) \1', 'ala ma 41 123 kota')
```
#### lookahead ( to sa takie assercje):
```
re.search(r'ma kot', 'ala ma kot')
re.search(r'ma kot(?=[ay])', 'ala ma kot')
re.search(r'ma kot(?=[ay])', 'ala ma kotka')
re.search(r'ma kot(?=[ay])', 'ala ma koty')
re.search(r'ma kot(?=[ay])', 'ala ma kota')
re.search(r'ma kot(?![ay])', 'ala ma kot')
re.search(r'ma kot(?![ay])', 'ala ma kotka')
re.search(r'ma kot(?![ay])', 'ala ma koty')
re.search(r'ma kot(?![ay])', 'ala ma kota')
```
#### named groups
```
r = re.search(r'ma (?P<ilepsow>\d+) kotow i (?P<ilekotow>\d+) psow', 'ala ma 100 kotow i 200 psow')
r.groups()
r.groups('ilepsow')
r.groups('ilekotow')
```
#### re.split
```
('a,b.c,d').split(',')
('a,b.c,d').split(',')
('a,b.c,d').split(',.')
re.split(r',', 'a,b.c,d')
re.split(r'[.,]', 'a,b.c,d')
```
#### \w word character
```
\w - matchuje Unicod word character , jeżeli flaga ASCII to [a-zA-Z0-9_]
\w - odwrotne do \W, jezeli flaga ASCI to [^a-zA-Z0-9_]
re.findall(r'\w+', 'ala ma 3 koty.')
re.findall(r'\W+', 'ala ma 3 koty.')
```
#### początek albo koniec słowa | word boundary
```
re.search(r'\bkot\b', 'Ala ma kota')
re.search(r'\bkot\b', 'Ala ma kot')
re.search(r'\bkot\b', 'Ala ma kot.')
re.search(r'\bkot\b', 'Ala ma kot ')
re.search(r'\Bot\B', 'Ala ma kot ')
re.search(r'\Bot\B', 'Ala ma kota ')
```
#### MULTILINE
```
re.findall(r'^Ma', 'Ma kota Ala\nMa psa Jacek')
re.findall(r'^Ma', 'Ma kota Ala\nMa psa Jacek', re.MULTILINE)
```
#### RE.COMPILE
## zajęcia 6
instalacja https://pypi.org/project/google-re2/
### DFA i NDFA
```
import re2 as re
n = 50
regexp = "a?"*n+"a"*n
s = "a"*n
re.match(regexp, s)
```
```
re.match(r"(\d)abc\1", "3abc3") # re2 nie obsługuje backreferencji
```
re2 max memory - podniesienie limitu
time # mierzenie czasu działania
gdyby ktoś chciał poczytać więcej:
https://swtch.com/~rsc/regexp/regexp1.html
### UTF-8
```
c = ""
ord(c)
chr(8459)
8* 16**2 + 0 * 16**(1) + 0*16**(0)
15*16**3 + 15* 16**2 + 15 * 16**(1) + 15*16**(0)
```
```
xxd -b file
xxd file
```
termin oddawania zadań - 15. listopada
## Zajęcia 7
https://www.openfst.org/twiki/bin/view/GRM/Thrax
https://www.cs.jhu.edu/~jason/465/hw-ofst/hw-ofst.pdf
Wszystkie zadania proszę robić na wzór `TaskH00`. Proszę umieszczać gramatykę w pliku `grammar.grm` oraz
opisywać finalną regułę nazwą `FinalRule`.
## KOLOKWIUM
Operatory, obowiązujące na kolokwium
====================================
* kwantyfikatory `-` `*` `+` `?` `{n}` `{n,}` `{n, m}`
* alternatywa — `|`
* klasy znaków — `[...]`
* zanegowane klasy znaków — `[^...]`
* dowolny znak — `.`
* unieważnianie znaków specjalnych — \
* operatory zakotwiczające — `^` `$`
Na kolokwium do każdego z 4 pytań będą 3 podpunkty. Na każdy podpunkt odpowiadamy TAK/NIE. Czas trwania to 15 minut.
- zawsze daszek i dolar
- nie bierzemy pod uwagę capturing (jeżeli są pytania o równoważne)
- proponuję wydrukować cały test w wersji bez opdowiedzi i sprawdzać
Do zaliczenia należy zdobyć conajmniej 10 punktów.

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Read a description of a non-deterministic finite-state automaton in the AT&T format
(without weights) from the file in the first argument.
Read strings from the standard input.
If a string is accepted by the
automaton, write YES, otherwise- write NO.
The program is invoked like this: python run.py test1.arg test1.in test1.out
Note that not all transitions must be included in description.
If no transition is given for the given state and letter, write NO.

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NO
NO
YES
YES
NO
NO
NO

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aaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
xyz
aba
a

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0 1 x
1 2 y
2 3 z
0 4 y
0 4 z
1 4 x
1 4 z
2 4 x
2 4 y
3 4 x
3 4 y
3 4 z
4 4 x
4 4 y
4 4 z
3

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NO
YES
NO
NO
NO
NO
NO
NO
NO

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xxyz
xyz
xy
zz
xxy
yzx
x
xyzz

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0 1 a
1 0 a
1 2 b
2 4 c
1 3 b
3
4

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YES
YES
NO
NO
NO
YES
NO
YES

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abc
ab
abcd
aaaabc
aaaaaaaabc
aaaaaaabc
zzz
aaaaaaabc

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Use a non deterministic finite-state automaton (FSA) engine from the TaskC00.
Create your own non deterministic FSA description to check whether the string second letter
from right is 'b'.
Don't use external files like in TaskF00 (description should be included in run file).
The alphabet is "a", "b", "C"
Read strings from the standard input.
If a string is accepted by the
automaton, write YES, otherwise- write NO.

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YES
YES
NO
NO
NO
YES

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abc
abbc
bca
b
abaa
aaacbb

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Use a non deterministic finite-state automaton (FSA) engine from the TaskC00.
Create your own non deterministic FSA description to check whether the string
ends with "ab"
Don't use external files like in TaskF00 (description should be included in run file).
The alphabet is "a", "b", "C"
Read strings from the standard input.
If a string is accepted by the
automaton, write YES, otherwise- write NO.

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YES
NO
YES
NO
YES
NO

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ab
a
abbab
bbbbb
ababaab
b

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Use a non deterministic finite-state automaton (FSA) engine from the TaskC00.
Create your own non deterministic FSA description to check whether the string
contains "abc"
Don't use external files like in TaskF00 (description should be included in run file).
The alphabet is "a", "b", "c"
Read strings from the standard input.
If a string is accepted by the
automaton, write YES, otherwise- write NO.

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YES
YES
YES
NO
NO
NO
NO

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abc
acabc
acabccb
abbab
bbbbb
ababaab
bc

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Deterministic automaton III
===========================
Read a description of a finite-state automaton in the AT&T format
(without weights) from the file in the first argument. Then, read strings from the
standard input. If a string is
accepted by the automated, write YES, a space and the string on the
standard output, otherwise — write NO, a space and the string.
If there is a non-determinism in the automaton, the first transition should be chosen.
The automaton can contain epsilon transitions ("<eps>" instead of a
character). They should be interpreted as follows: an epsilon
transition can be used (without "eating" a character from the input),
if there is no other transition applicable. You can assume that there
is at most one epsilon transition from a given state and that there
are no cycles with epsilon transition.
Your program does not have to check whether the description is correct
and whether the automaton is deterministic. You can assume that the
automaton does not contain epsilon transitions.

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0 1 a
1 0 a
1 2 b
2 4 c
1 3 <eps>
3 4 d
3
4

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TRUE a
FALSE aa
TRUE aaa
TRUE abc
TRUE aaabc
FALSE aaabcd
FALSE aabc
FALSE abd
TRUE ad
FALSE aad

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a
aa
aaa
abc
aaabc
aaabcd
aabc
abd
ad
aad

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FALSE aaa
FALSE aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
TRUE aaaa
TRUE aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
FALSE xyz
FALSE aba
FALSE a

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aaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
xyz
aba
a

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# prosty automat akceptujący tylko napis "abc"
0 1 a
1 2 b
2 3 c
3

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FALSE a
FALSE ab
TRUE abc
FALSE abcd
FALSE aaaaab
TRUE abc
FALSE xyz
FALSE 0

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a
ab
abc
abcd
aaaaab
abc
xyz
0

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@ -1,9 +0,0 @@
# automat akceptujący napis "ab*c" (b powielony dowolną liczbę razy) i "kot"
0 1 a
1 1 b
1 2 c
0 3 k
3 4 o
4 5 t
2
5

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@ -1,9 +0,0 @@
TRUE kot
TRUE ac
TRUE abc
TRUE abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbc
FALSE abcd
FALSE abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbcccccc
FALSE kotek
FALSE kotabc
TRUE kot

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@ -1,9 +0,0 @@
kot
ac
abc
abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbc
abcd
abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbcccccc
kotek
kotabc
kot

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Dictionary
==========
Your program should read a finite-state automaton from file in the first argument.
The automaton is deterministic, you can assume it does not contain
cycles.
Each automaton path is labeled with a symbol sequence of the following form:
<input word>;<description>
e.g.:
biały;ADJ
dom;N
piła;N
piła;V
stali;N
stali;V
stali;ADJ
Next you should read words from the standard input.
For each word, you should all automaton
paths that begin a given word, the following symbol is ';'
(semicolon), e.g. for the word 'dom' we are looking for paths
beginning with 'dom;'. If there is no such path, the following message
should be printed:
<input word>;OOV
For instance, for the automaton given above and the input:
budynek
dom
piła
we should get:
budynek;OOV
dom;N
piła;N
piła;V
If there is more than one path for a given word, they should be given in alphabetical order.
The program does not have to check whether the automaton is correct
and whether it is deterministic and does not contain cycles.

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0 1 b
0 2 d
0 3 p
0 4 s
1 5 i
2 6 o
3 7 i
4 8 t
5 9 a
6 10 m
7 11 ł
8 12 a
9 13 ł
10 14 ;
11 15 a
12 16 l
13 17 y
14 24 N
15 18 ;
16 19 i
17 20 ;
18 24 N
18 24 V
19 21 ;
20 22 A
21 22 A
21 24 N
21 24 V
22 23 D
23 24 J
24

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@ -1 +0,0 @@
dom;N

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dom

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@ -1,7 +0,0 @@
arbuz;N
arbuza;N
arbuzowi;ADJ
arbuzowi;N
azylant;N
azylanci;N
azylantowie;OOV

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arbuz
arbuza
arbuzowi
azylant
azylanci
azylantowie

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@ -1,31 +0,0 @@
0 1 b
0 2 d
0 3 p
0 4 s
1 5 i
2 6 o
3 7 i
4 8 t
5 9 a
6 10 m
7 11 ł
8 12 a
9 13 ł
10 14 ;
11 15 a
12 16 l
13 17 y
14 24 N
15 18 ;
16 19 i
17 20 ;
18 24 N
18 24 V
19 21 ;
20 22 A
21 22 A
21 24 N
21 24 V
22 23 D
23 24 J
24

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piła;N
piła;V

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piła

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0 1 b
0 2 d
0 3 p
0 4 s
1 5 i
2 6 o
3 7 i
4 8 t
5 9 a
6 10 m
7 11 ł
8 12 a
9 13 ł
10 14 ;
11 15 a
12 16 l
13 17 y
14 24 N
15 18 ;
16 19 i
17 20 ;
18 24 N
18 24 V
19 21 ;
20 22 A
21 22 A
21 24 N
21 24 V
22 23 D
23 24 J
24

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budynek;OOV

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budynek

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Paths
======
Your program should read a finite-state automaton from
the standard input.
The automaton is deterministic, you can assume it does not contain
cycles. The automaton alphabet is the set of Polish lower-case letters
(English letters plus: ą, ć, ę, ł, ń, ó, ś, ź and ż).
Your program should print, on standard output, all the paths of the
automaton in alphabetical order (to be precise: order induced by byte
codes of strings, not according to the standard Polish order). "Print
a path" means print a text line containing all subsequent characters.
The program does not have to check whether the automaton is correct
and whether it is deterministic and does not contain cycles.
Weights (if any) should be disregarded.
NOTE 1. You can add `LANG=C sort` to your Bash wrapper for the write sort.

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a

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biały
dom
piła
stali

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0 1 b
0 2 d
0 3 p
0 4 s
1 5 i
2 6 o
3 7 i
4 8 t
5 9 a
6 14 m
7 10 ł
8 11 a
9 12 ł
10 14 a
11 13 l
12 14 y
13 14 i
14

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biały
piła
stali

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@ -1,18 +0,0 @@
0 1 b
0 2 d
0 3 p
0 4 s
1 5 i
2 6 o
3 7 i
4 8 t
5 9 a
6 15 m
7 10 ł
8 11 a
9 12 ł
10 14 a
11 13 l
12 14 y
13 14 i
14