2023-10-29 22:59:51 +01:00
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Deterministic automaton III
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===========================
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Read a description of a finite-state automaton in the AT&T format
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(without weights) from the file in the first argument. Then, read strings from the
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standard input. If a string is
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2023-11-12 15:41:40 +01:00
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accepted by the automaton, write TRUE, a space and the string on the
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standard output, otherwise — write FALSE, a space and the string.
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2023-10-29 22:59:51 +01:00
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If there is a non-determinism in the automaton, the first transition should be chosen.
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The automaton can contain epsilon transitions ("<eps>" instead of a
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character). They should be interpreted as follows: an epsilon
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transition can be used (without "eating" a character from the input),
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if there is no other transition applicable. You can assume that there
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is at most one epsilon transition from a given state and that there
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are no cycles with epsilon transition.
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Your program does not have to check whether the description is correct
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and whether the automaton is deterministic.
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2023-10-29 22:59:51 +01:00
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2023-11-24 20:39:14 +01:00
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long.arg - this automaton accepts two texts - "aaaa" and "a" replicated 4038 times.
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simple1.arg - simple automaton accepting only text "abc"
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simple2.arg - automaton accepting text "ab*c" (b replicated any number of times) and "kot"
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2023-10-29 22:59:51 +01:00
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POINTS: 3
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DEADLINE: 2023-11-12 23:59:59
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REMAINDER: 0/3
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