Merge remote-tracking branch 'wmi_upstream/main'
This commit is contained in:
Pawel Felcyn
commit
1820fc5e14
344
README.md
344
README.md
@ -23,347 +23,3 @@ W ten sposób będziemy aktualizować zadania co zajęcia.
|
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Zadania robimy do końca soboty poprzedzającej zajęcia
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Rozwiązanie zapisujemy w pliku run.py
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## Zajęcia 2 Wyrażenia regularne
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Dokumentacja wyrażeń regularnych w python3: https://docs.python.org/3/library/re.html
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### Podstawowe funkcje
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search - zwraca pierwsze dopasowanie w napisie
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findall - zwraca listę wszystkich dopasowań (nienakładających się na siebie)
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match - zwraca dopasowanie od początku string
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To tylko podstawowe funkcje, z których będziemy korzystać. W dokumentacji opisane są wszystkie.
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### Obiekt match
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```
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import re
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answer = re.search('na','banan')
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print(answer)
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print(answer.start())
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print(answer.end())
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print(answer.group())
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answer = re.search('na','kabanos')
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print(answer)
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type(answer)
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if answer:
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print(answer.group())
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else:
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pass
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```
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### Metaznaki
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- [] - zbiór znaków
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- . - jakikolwiek znak
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- ^ - początek napisu
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- $ - koniec napisu
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- ? - znak występuje lub nie występuje
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- \* - zero albo więcej pojawień się
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- \+ - jeden albo więcej pojawień się
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- {} - dokładnie tyle pojawień się
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- | - lub
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- () - grupa
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- \ -znak ucieczki
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- \d digit
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- \D nie digit
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- \s whitespace
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- \S niewhitespace
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### Flagi
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Można użyć specjalnych flag, np:
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`re.search('ma', 'AlA Ma KoTa', re.IGNORECASE)`.
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### Przykłady (objaśnienia na laboratoriach)
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Do nauki lepiej użyć pythona w wersji interaktywnej, a najlepiej ipython.
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```
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import re
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text = 'Ala ma kota i hamak, oraz 150 bananów.'
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re.search('ma',text)
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re.match('ma',text)
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re.match('Ala ma',text)
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re.findall('ma',text)
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re.findall('[mn]a',text)
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re.findall('[0-9]',text)
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re.findall('[0-9abc]',text)
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re.findall('[a-z][a-z]ma[a-z]',text)
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re.findall('[a-zA-Z][a-zA-Z]ma[a-zA-z0-9]',text)
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re.findall('\d',text)
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re.search('[0-9][0-9][0-9]',text)
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re.search('[\d][\d][\d]',text)
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re.search('\d{2}',text)
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re.search('\d{3}',text)
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re.search('\d+',text)
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re.search('\d+ bananów',text)
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re.search('\d* bananów','Ala ma dużo bananów')
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re.search('\d* bananów',text)
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re.search('ma \d? bananów','Ala ma 5 bananów')
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re.search('ma ?\d? bananów','Ala ma bananów')
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re.search('ma( \d)? bananów','Ala ma bananów')
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re.search('\d+ bananów','Ala ma 10 bananów albo 20 bananów')
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re.search('\d+ bananów$','Ala ma 10 bananów albo 20 bananów')
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text = 'Ala ma kota i hamak, oraz 150 bananów.'
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re.search('\d+ bananów',text)
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re.search('\d+\sbananów',text)
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re.search('kota . hamak',text)
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re.search('kota . hamak','Ala ma kota z hamakiem')
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re.search('kota .* hamak','Ala ma kota lub hamak')
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re.search('\.',text)
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re.search('kota|psa','Ala ma kota lub hamak')
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re.findall('kota|psa','Ala ma kota lub psa')
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re.search('kota (i|lub) psa','Ala ma kota lub psa')
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re.search('mam (kota).*(kota|psa)','Ja mam kota. Ala ma psa.').group(0)
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re.search('mam (kota).*(kota|psa)','Ja mam kota. Ala ma psa.').group(1)
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re.search('mam (kota).*(kota|psa)','Ja mam kota. Ala ma psa.').group(2)
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```
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### Przykłady wyrażenia regularne 2 (objaśnienia na laboratoriach)
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#### ^
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```
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re.search('[0-9]+', '123-456-789')
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re.search('[^0-9][0-9]+[^0-9]', '123-456-789')
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```
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#### cudzysłów
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'' oraz "" - oznaczają to samo w pythonie
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' ala ma psa o imieniu "Burek"'
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" ala ma psa o imieniu 'Burek' "
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' ala ma psa o imieniu \'Burek\' '
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" ala ma psa o imieniu \"Burek\" "
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#### multiline string
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#### raw string
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przy raw string znaki \ traktowane są jako zwykłe znaki \
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chociaż nawet w raw string nadal są escapowane (ale wtedy \ pozostają również w stringu bez zmian)
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https://docs.python.org/3/reference/lexical_analysis.html
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dobra praktyka - wszędzie escapować
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```
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'\\'
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print('\\')
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r'\\'
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print(r'\\')
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print("abcd")
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print("ab\cd")
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print(r"ab\cd")
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print("ab\nd")
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print(r"ab\nd")
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print("\"")
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print(r"\"")
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print("\")
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print(r"\")
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re.search('\\', r'a\bc')
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re.search(r'\\', r'a\bc')
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re.search('\\\\', r'a\bc')
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```
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#### RE SUB
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```
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re.sub(pattern, replacement, string)
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re.sub('a','b', 'ala ma kota')
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```
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#### backreferencje:
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```
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re.search(r' \d+ \d+', 'ala ma 41 41 kota')
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re.search(r' \d+ \d+', 'ala ma 41 123 kota')
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re.search(r' (\d+) \1', 'ala ma 41 41 kota')
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re.search(r' (\d+) \1', 'ala ma 41 123 kota')
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```
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#### lookahead ( to sa takie assercje):
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```
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re.search(r'ma kot', 'ala ma kot')
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re.search(r'ma kot(?=[ay])', 'ala ma kot')
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re.search(r'ma kot(?=[ay])', 'ala ma kotka')
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re.search(r'ma kot(?=[ay])', 'ala ma koty')
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re.search(r'ma kot(?=[ay])', 'ala ma kota')
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re.search(r'ma kot(?![ay])', 'ala ma kot')
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re.search(r'ma kot(?![ay])', 'ala ma kotka')
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re.search(r'ma kot(?![ay])', 'ala ma koty')
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re.search(r'ma kot(?![ay])', 'ala ma kota')
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```
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#### named groups
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```
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r = re.search(r'ma (?P<ilepsow>\d+) kotow i (?P<ilekotow>\d+) psow', 'ala ma 100 kotow i 200 psow')
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r.groups()
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r.groups('ilepsow')
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r.groups('ilekotow')
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```
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#### re.split
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```
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('a,b.c,d').split(',')
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('a,b.c,d').split(',')
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('a,b.c,d').split(',.')
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re.split(r',', 'a,b.c,d')
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re.split(r'[.,]', 'a,b.c,d')
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```
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#### \w word character
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```
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\w - matchuje Unicod word character , jeżeli flaga ASCII to [a-zA-Z0-9_]
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\w - odwrotne do \W, jezeli flaga ASCI to [^a-zA-Z0-9_]
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re.findall(r'\w+', 'ala ma 3 koty.')
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re.findall(r'\W+', 'ala ma 3 koty.')
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```
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#### początek albo koniec słowa | word boundary
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```
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re.search(r'\bkot\b', 'Ala ma kota')
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re.search(r'\bkot\b', 'Ala ma kot')
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re.search(r'\bkot\b', 'Ala ma kot.')
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re.search(r'\bkot\b', 'Ala ma kot ')
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re.search(r'\Bot\B', 'Ala ma kot ')
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re.search(r'\Bot\B', 'Ala ma kota ')
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```
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#### MULTILINE
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```
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re.findall(r'^Ma', 'Ma kota Ala\nMa psa Jacek')
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re.findall(r'^Ma', 'Ma kota Ala\nMa psa Jacek', re.MULTILINE)
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```
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#### RE.COMPILE
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## zajęcia 6
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instalacja https://pypi.org/project/google-re2/
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### DFA i NDFA
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```
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import re2 as re
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n = 50
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regexp = "a?"*n+"a"*n
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s = "a"*n
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re.match(regexp, s)
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```
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```
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re.match(r"(\d)abc\1", "3abc3") # re2 nie obsługuje backreferencji
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```
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re2 max memory - podniesienie limitu
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time # mierzenie czasu działania
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gdyby ktoś chciał poczytać więcej:
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https://swtch.com/~rsc/regexp/regexp1.html
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### UTF-8
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```
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c = "ℋ"
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ord(c)
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chr(8459)
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8* 16**2 + 0 * 16**(1) + 0*16**(0)
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15*16**3 + 15* 16**2 + 15 * 16**(1) + 15*16**(0)
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```
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```
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xxd -b file
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xxd file
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```
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termin oddawania zadań - 15. listopada
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## Zajęcia 7
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https://www.openfst.org/twiki/bin/view/GRM/Thrax
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https://www.cs.jhu.edu/~jason/465/hw-ofst/hw-ofst.pdf
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Wszystkie zadania proszę robić na wzór `TaskH00`. Proszę umieszczać gramatykę w pliku `grammar.grm` oraz
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opisywać finalną regułę nazwą `FinalRule`.
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## KOLOKWIUM
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Operatory, obowiązujące na kolokwium
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====================================
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* kwantyfikatory `-` `*` `+` `?` `{n}` `{n,}` `{n, m}`
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* alternatywa — `|`
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* klasy znaków — `[...]`
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* zanegowane klasy znaków — `[^...]`
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* dowolny znak — `.`
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* unieważnianie znaków specjalnych — \
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* operatory zakotwiczające — `^` `$`
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Na kolokwium do każdego z 4 pytań będą 3 podpunkty. Na każdy podpunkt odpowiadamy TAK/NIE. Czas trwania to 15 minut.
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- zawsze daszek i dolar
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- nie bierzemy pod uwagę capturing (jeżeli są pytania o równoważne)
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- proponuję wydrukować cały test w wersji bez opdowiedzi i sprawdzać
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Do zaliczenia należy zdobyć conajmniej 10 punktów.
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12
TaskC00/description.txt
Normal file
12
TaskC00/description.txt
Normal file
@ -0,0 +1,12 @@
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Read a description of a non-deterministic finite-state automaton in the AT&T format
|
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(without weights) from the file in the first argument.
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Read strings from the standard input.
|
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If a string is accepted by the
|
||||
automaton, write YES, otherwise- write NO.
|
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The program is invoked like this: python run.py test1.arg test1.in test1.out
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Note that not all transitions must be included in description.
|
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If no transition is given for the given state and letter, write NO.
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4041
TaskC00/long.arg
Normal file
4041
TaskC00/long.arg
Normal file
File diff suppressed because it is too large
Load Diff
7
TaskC00/long.exp
Normal file
7
TaskC00/long.exp
Normal file
@ -0,0 +1,7 @@
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NO
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NO
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YES
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YES
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NO
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NO
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NO
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7
TaskC00/long.in
Normal file
7
TaskC00/long.in
Normal file
@ -0,0 +1,7 @@
|
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aaa
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aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
|
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aaaa
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||||
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
|
||||
xyz
|
||||
aba
|
||||
a
|
||||
16
TaskC00/test1.arg
Normal file
16
TaskC00/test1.arg
Normal file
@ -0,0 +1,16 @@
|
||||
0 1 x
|
||||
1 2 y
|
||||
2 3 z
|
||||
0 4 y
|
||||
0 4 z
|
||||
1 4 x
|
||||
1 4 z
|
||||
2 4 x
|
||||
2 4 y
|
||||
3 4 x
|
||||
3 4 y
|
||||
3 4 z
|
||||
4 4 x
|
||||
4 4 y
|
||||
4 4 z
|
||||
3
|
||||
9
TaskC00/test1.exp
Normal file
9
TaskC00/test1.exp
Normal file
@ -0,0 +1,9 @@
|
||||
NO
|
||||
YES
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
9
TaskC00/test1.in
Normal file
9
TaskC00/test1.in
Normal file
@ -0,0 +1,9 @@
|
||||
xxyz
|
||||
xyz
|
||||
xy
|
||||
zz
|
||||
xxy
|
||||
yzx
|
||||
|
||||
x
|
||||
xyzz
|
||||
7
TaskC00/testnfa.arg
Normal file
7
TaskC00/testnfa.arg
Normal file
@ -0,0 +1,7 @@
|
||||
0 1 a
|
||||
1 0 a
|
||||
1 2 b
|
||||
2 4 c
|
||||
1 3 b
|
||||
3
|
||||
4
|
||||
8
TaskC00/testnfa.exp
Normal file
8
TaskC00/testnfa.exp
Normal file
@ -0,0 +1,8 @@
|
||||
YES
|
||||
YES
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
YES
|
||||
NO
|
||||
YES
|
||||
8
TaskC00/testnfa.in
Normal file
8
TaskC00/testnfa.in
Normal file
@ -0,0 +1,8 @@
|
||||
abc
|
||||
ab
|
||||
abcd
|
||||
aaaabc
|
||||
aaaaaaaabc
|
||||
aaaaaaabc
|
||||
zzz
|
||||
aaaaaaabc
|
||||
11
TaskC01/description.txt
Normal file
11
TaskC01/description.txt
Normal file
@ -0,0 +1,11 @@
|
||||
Use a non deterministic finite-state automaton (FSA) engine from the TaskC00.
|
||||
Create your own non deterministic FSA description to check whether the string second letter
|
||||
from right is 'b'.
|
||||
Don't use external files like in TaskF00 (description should be included in run file).
|
||||
|
||||
The alphabet is "a", "b", "C"
|
||||
|
||||
Read strings from the standard input.
|
||||
If a string is accepted by the
|
||||
automaton, write YES, otherwise- write NO.
|
||||
|
||||
6
TaskC01/test.exp
Normal file
6
TaskC01/test.exp
Normal file
@ -0,0 +1,6 @@
|
||||
YES
|
||||
YES
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
YES
|
||||
6
TaskC01/test.in
Normal file
6
TaskC01/test.in
Normal file
@ -0,0 +1,6 @@
|
||||
abc
|
||||
abbc
|
||||
bca
|
||||
b
|
||||
abaa
|
||||
aaacbb
|
||||
11
TaskC02/description.txt
Normal file
11
TaskC02/description.txt
Normal file
@ -0,0 +1,11 @@
|
||||
Use a non deterministic finite-state automaton (FSA) engine from the TaskC00.
|
||||
Create your own non deterministic FSA description to check whether the string
|
||||
ends with "ab"
|
||||
Don't use external files like in TaskF00 (description should be included in run file).
|
||||
|
||||
The alphabet is "a", "b", "C"
|
||||
|
||||
Read strings from the standard input.
|
||||
If a string is accepted by the
|
||||
automaton, write YES, otherwise- write NO.
|
||||
|
||||
6
TaskC02/test.exp
Normal file
6
TaskC02/test.exp
Normal file
@ -0,0 +1,6 @@
|
||||
YES
|
||||
NO
|
||||
YES
|
||||
NO
|
||||
YES
|
||||
NO
|
||||
6
TaskC02/test.in
Normal file
6
TaskC02/test.in
Normal file
@ -0,0 +1,6 @@
|
||||
ab
|
||||
a
|
||||
abbab
|
||||
bbbbb
|
||||
ababaab
|
||||
b
|
||||
10
TaskC03/description.txt
Normal file
10
TaskC03/description.txt
Normal file
@ -0,0 +1,10 @@
|
||||
Use a non deterministic finite-state automaton (FSA) engine from the TaskC00.
|
||||
Create your own non deterministic FSA description to check whether the string
|
||||
contains "abc"
|
||||
Don't use external files like in TaskF00 (description should be included in run file).
|
||||
|
||||
The alphabet is "a", "b", "c"
|
||||
|
||||
Read strings from the standard input.
|
||||
If a string is accepted by the
|
||||
automaton, write YES, otherwise- write NO.
|
||||
7
TaskC03/test.exp
Normal file
7
TaskC03/test.exp
Normal file
@ -0,0 +1,7 @@
|
||||
YES
|
||||
YES
|
||||
YES
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
NO
|
||||
7
TaskC03/test.in
Normal file
7
TaskC03/test.in
Normal file
@ -0,0 +1,7 @@
|
||||
abc
|
||||
acabc
|
||||
acabccb
|
||||
abbab
|
||||
bbbbb
|
||||
ababaab
|
||||
bc
|
||||
22
TaskC04/description.txt
Normal file
22
TaskC04/description.txt
Normal file
@ -0,0 +1,22 @@
|
||||
Deterministic automaton III
|
||||
===========================
|
||||
|
||||
Read a description of a finite-state automaton in the AT&T format
|
||||
(without weights) from the file in the first argument. Then, read strings from the
|
||||
standard input. If a string is
|
||||
accepted by the automated, write YES, a space and the string on the
|
||||
standard output, otherwise — write NO, a space and the string.
|
||||
|
||||
If there is a non-determinism in the automaton, the first transition should be chosen.
|
||||
|
||||
The automaton can contain epsilon transitions ("<eps>" instead of a
|
||||
character). They should be interpreted as follows: an epsilon
|
||||
transition can be used (without "eating" a character from the input),
|
||||
if there is no other transition applicable. You can assume that there
|
||||
is at most one epsilon transition from a given state and that there
|
||||
are no cycles with epsilon transition.
|
||||
|
||||
Your program does not have to check whether the description is correct
|
||||
and whether the automaton is deterministic. You can assume that the
|
||||
automaton does not contain epsilon transitions.
|
||||
|
||||
8
TaskC04/eps.arg
Normal file
8
TaskC04/eps.arg
Normal file
@ -0,0 +1,8 @@
|
||||
0 1 a
|
||||
1 0 a
|
||||
1 2 b
|
||||
2 4 c
|
||||
1 3 <eps>
|
||||
3 4 d
|
||||
3
|
||||
4
|
||||
10
TaskC04/eps.exp
Normal file
10
TaskC04/eps.exp
Normal file
@ -0,0 +1,10 @@
|
||||
TRUE a
|
||||
FALSE aa
|
||||
TRUE aaa
|
||||
TRUE abc
|
||||
TRUE aaabc
|
||||
FALSE aaabcd
|
||||
FALSE aabc
|
||||
FALSE abd
|
||||
TRUE ad
|
||||
FALSE aad
|
||||
10
TaskC04/eps.in
Normal file
10
TaskC04/eps.in
Normal file
@ -0,0 +1,10 @@
|
||||
a
|
||||
aa
|
||||
aaa
|
||||
abc
|
||||
aaabc
|
||||
aaabcd
|
||||
aabc
|
||||
abd
|
||||
ad
|
||||
aad
|
||||
4041
TaskC04/long.arg
Normal file
4041
TaskC04/long.arg
Normal file
File diff suppressed because it is too large
Load Diff
7
TaskC04/long.exp
Normal file
7
TaskC04/long.exp
Normal file
@ -0,0 +1,7 @@
|
||||
FALSE aaa
|
||||
FALSE aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
|
||||
TRUE aaaa
|
||||
TRUE aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
|
||||
FALSE xyz
|
||||
FALSE aba
|
||||
FALSE a
|
||||
7
TaskC04/long.in
Normal file
7
TaskC04/long.in
Normal file
@ -0,0 +1,7 @@
|
||||
aaa
|
||||
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
|
||||
aaaa
|
||||
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
|
||||
xyz
|
||||
aba
|
||||
a
|
||||
5
TaskC04/simple1.arg
Normal file
5
TaskC04/simple1.arg
Normal file
@ -0,0 +1,5 @@
|
||||
# prosty automat akceptujący tylko napis "abc"
|
||||
0 1 a
|
||||
1 2 b
|
||||
2 3 c
|
||||
3
|
||||
8
TaskC04/simple1.exp
Normal file
8
TaskC04/simple1.exp
Normal file
@ -0,0 +1,8 @@
|
||||
FALSE a
|
||||
FALSE ab
|
||||
TRUE abc
|
||||
FALSE abcd
|
||||
FALSE aaaaab
|
||||
TRUE abc
|
||||
FALSE xyz
|
||||
FALSE 0
|
||||
8
TaskC04/simple1.in
Normal file
8
TaskC04/simple1.in
Normal file
@ -0,0 +1,8 @@
|
||||
a
|
||||
ab
|
||||
abc
|
||||
abcd
|
||||
aaaaab
|
||||
abc
|
||||
xyz
|
||||
0
|
||||
9
TaskC04/simple2.arg
Normal file
9
TaskC04/simple2.arg
Normal file
@ -0,0 +1,9 @@
|
||||
# automat akceptujący napis "ab*c" (b powielony dowolną liczbę razy) i "kot"
|
||||
0 1 a
|
||||
1 1 b
|
||||
1 2 c
|
||||
0 3 k
|
||||
3 4 o
|
||||
4 5 t
|
||||
2
|
||||
5
|
||||
9
TaskC04/simple2.exp
Normal file
9
TaskC04/simple2.exp
Normal file
@ -0,0 +1,9 @@
|
||||
TRUE kot
|
||||
TRUE ac
|
||||
TRUE abc
|
||||
TRUE abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbc
|
||||
FALSE abcd
|
||||
FALSE abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbcccccc
|
||||
FALSE kotek
|
||||
FALSE kotabc
|
||||
TRUE kot
|
||||
9
TaskC04/simple2.in
Normal file
9
TaskC04/simple2.in
Normal file
@ -0,0 +1,9 @@
|
||||
kot
|
||||
ac
|
||||
abc
|
||||
abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbc
|
||||
abcd
|
||||
abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbcccccc
|
||||
kotek
|
||||
kotabc
|
||||
kot
|
||||
49
TaskC05/description.txt
Normal file
49
TaskC05/description.txt
Normal file
@ -0,0 +1,49 @@
|
||||
Dictionary
|
||||
==========
|
||||
|
||||
Your program should read a finite-state automaton from file in the first argument.
|
||||
The automaton is deterministic, you can assume it does not contain
|
||||
cycles.
|
||||
|
||||
Each automaton path is labeled with a symbol sequence of the following form:
|
||||
|
||||
<input word>;<description>
|
||||
|
||||
e.g.:
|
||||
|
||||
biały;ADJ
|
||||
dom;N
|
||||
piła;N
|
||||
piła;V
|
||||
stali;N
|
||||
stali;V
|
||||
stali;ADJ
|
||||
|
||||
Next you should read words from the standard input.
|
||||
For each word, you should all automaton
|
||||
paths that begin a given word, the following symbol is ';'
|
||||
(semicolon), e.g. for the word 'dom' we are looking for paths
|
||||
beginning with 'dom;'. If there is no such path, the following message
|
||||
should be printed:
|
||||
|
||||
<input word>;OOV
|
||||
|
||||
For instance, for the automaton given above and the input:
|
||||
|
||||
budynek
|
||||
dom
|
||||
piła
|
||||
|
||||
we should get:
|
||||
|
||||
budynek;OOV
|
||||
dom;N
|
||||
piła;N
|
||||
piła;V
|
||||
|
||||
If there is more than one path for a given word, they should be given in alphabetical order.
|
||||
|
||||
The program does not have to check whether the automaton is correct
|
||||
and whether it is deterministic and does not contain cycles.
|
||||
|
||||
|
||||
31
TaskC05/elem.arg
Normal file
31
TaskC05/elem.arg
Normal file
@ -0,0 +1,31 @@
|
||||
0 1 b
|
||||
0 2 d
|
||||
0 3 p
|
||||
0 4 s
|
||||
1 5 i
|
||||
2 6 o
|
||||
3 7 i
|
||||
4 8 t
|
||||
5 9 a
|
||||
6 10 m
|
||||
7 11 ł
|
||||
8 12 a
|
||||
9 13 ł
|
||||
10 14 ;
|
||||
11 15 a
|
||||
12 16 l
|
||||
13 17 y
|
||||
14 24 N
|
||||
15 18 ;
|
||||
16 19 i
|
||||
17 20 ;
|
||||
18 24 N
|
||||
18 24 V
|
||||
19 21 ;
|
||||
20 22 A
|
||||
21 22 A
|
||||
21 24 N
|
||||
21 24 V
|
||||
22 23 D
|
||||
23 24 J
|
||||
24
|
||||
1
TaskC05/elem.exp
Normal file
1
TaskC05/elem.exp
Normal file
@ -0,0 +1 @@
|
||||
dom;N
|
||||
1
TaskC05/elem.in
Normal file
1
TaskC05/elem.in
Normal file
@ -0,0 +1 @@
|
||||
dom
|
||||
15125
TaskC05/medium.arg
Normal file
15125
TaskC05/medium.arg
Normal file
File diff suppressed because it is too large
Load Diff
7
TaskC05/medium.exp
Normal file
7
TaskC05/medium.exp
Normal file
@ -0,0 +1,7 @@
|
||||
arbuz;N
|
||||
arbuza;N
|
||||
arbuzowi;ADJ
|
||||
arbuzowi;N
|
||||
azylant;N
|
||||
azylanci;N
|
||||
azylantowie;OOV
|
||||
6
TaskC05/medium.in
Normal file
6
TaskC05/medium.in
Normal file
@ -0,0 +1,6 @@
|
||||
arbuz
|
||||
arbuza
|
||||
arbuzowi
|
||||
azylant
|
||||
azylanci
|
||||
azylantowie
|
||||
31
TaskC05/multi.arg
Normal file
31
TaskC05/multi.arg
Normal file
@ -0,0 +1,31 @@
|
||||
0 1 b
|
||||
0 2 d
|
||||
0 3 p
|
||||
0 4 s
|
||||
1 5 i
|
||||
2 6 o
|
||||
3 7 i
|
||||
4 8 t
|
||||
5 9 a
|
||||
6 10 m
|
||||
7 11 ł
|
||||
8 12 a
|
||||
9 13 ł
|
||||
10 14 ;
|
||||
11 15 a
|
||||
12 16 l
|
||||
13 17 y
|
||||
14 24 N
|
||||
15 18 ;
|
||||
16 19 i
|
||||
17 20 ;
|
||||
18 24 N
|
||||
18 24 V
|
||||
19 21 ;
|
||||
20 22 A
|
||||
21 22 A
|
||||
21 24 N
|
||||
21 24 V
|
||||
22 23 D
|
||||
23 24 J
|
||||
24
|
||||
2
TaskC05/multi.exp
Normal file
2
TaskC05/multi.exp
Normal file
@ -0,0 +1,2 @@
|
||||
piła;N
|
||||
piła;V
|
||||
1
TaskC05/multi.in
Normal file
1
TaskC05/multi.in
Normal file
@ -0,0 +1 @@
|
||||
piła
|
||||
31
TaskC05/oov.arg
Normal file
31
TaskC05/oov.arg
Normal file
@ -0,0 +1,31 @@
|
||||
0 1 b
|
||||
0 2 d
|
||||
0 3 p
|
||||
0 4 s
|
||||
1 5 i
|
||||
2 6 o
|
||||
3 7 i
|
||||
4 8 t
|
||||
5 9 a
|
||||
6 10 m
|
||||
7 11 ł
|
||||
8 12 a
|
||||
9 13 ł
|
||||
10 14 ;
|
||||
11 15 a
|
||||
12 16 l
|
||||
13 17 y
|
||||
14 24 N
|
||||
15 18 ;
|
||||
16 19 i
|
||||
17 20 ;
|
||||
18 24 N
|
||||
18 24 V
|
||||
19 21 ;
|
||||
20 22 A
|
||||
21 22 A
|
||||
21 24 N
|
||||
21 24 V
|
||||
22 23 D
|
||||
23 24 J
|
||||
24
|
||||
1
TaskC05/oov.exp
Normal file
1
TaskC05/oov.exp
Normal file
@ -0,0 +1 @@
|
||||
budynek;OOV
|
||||
1
TaskC05/oov.in
Normal file
1
TaskC05/oov.in
Normal file
@ -0,0 +1 @@
|
||||
budynek
|
||||
21
TaskC06/description.txt
Normal file
21
TaskC06/description.txt
Normal file
@ -0,0 +1,21 @@
|
||||
Paths
|
||||
======
|
||||
|
||||
Your program should read a finite-state automaton from
|
||||
the standard input.
|
||||
The automaton is deterministic, you can assume it does not contain
|
||||
cycles. The automaton alphabet is the set of Polish lower-case letters
|
||||
(English letters plus: ą, ć, ę, ł, ń, ó, ś, ź and ż).
|
||||
|
||||
Your program should print, on standard output, all the paths of the
|
||||
automaton in alphabetical order (to be precise: order induced by byte
|
||||
codes of strings, not according to the standard Polish order). "Print
|
||||
a path" means print a text line containing all subsequent characters.
|
||||
|
||||
The program does not have to check whether the automaton is correct
|
||||
and whether it is deterministic and does not contain cycles.
|
||||
|
||||
Weights (if any) should be disregarded.
|
||||
|
||||
NOTE 1. You can add `LANG=C sort` to your Bash wrapper for the write sort.
|
||||
|
||||
50648
TaskC06/medium.exp
Normal file
50648
TaskC06/medium.exp
Normal file
File diff suppressed because it is too large
Load Diff
14774
TaskC06/medium.in
Normal file
14774
TaskC06/medium.in
Normal file
File diff suppressed because it is too large
Load Diff
1
TaskC06/medium2.exp
Normal file
1
TaskC06/medium2.exp
Normal file
@ -0,0 +1 @@
|
||||
a
|
||||
13989
TaskC06/medium2.in
Normal file
13989
TaskC06/medium2.in
Normal file
File diff suppressed because it is too large
Load Diff
4
TaskC06/small.exp
Normal file
4
TaskC06/small.exp
Normal file
@ -0,0 +1,4 @@
|
||||
biały
|
||||
dom
|
||||
piła
|
||||
stali
|
||||
18
TaskC06/small.in
Normal file
18
TaskC06/small.in
Normal file
@ -0,0 +1,18 @@
|
||||
0 1 b
|
||||
0 2 d
|
||||
0 3 p
|
||||
0 4 s
|
||||
1 5 i
|
||||
2 6 o
|
||||
3 7 i
|
||||
4 8 t
|
||||
5 9 a
|
||||
6 14 m
|
||||
7 10 ł
|
||||
8 11 a
|
||||
9 12 ł
|
||||
10 14 a
|
||||
11 13 l
|
||||
12 14 y
|
||||
13 14 i
|
||||
14
|
||||
3
TaskC06/small2.exp
Normal file
3
TaskC06/small2.exp
Normal file
@ -0,0 +1,3 @@
|
||||
biały
|
||||
piła
|
||||
stali
|
||||
18
TaskC06/small2.in
Normal file
18
TaskC06/small2.in
Normal file
@ -0,0 +1,18 @@
|
||||
0 1 b
|
||||
0 2 d
|
||||
0 3 p
|
||||
0 4 s
|
||||
1 5 i
|
||||
2 6 o
|
||||
3 7 i
|
||||
4 8 t
|
||||
5 9 a
|
||||
6 15 m
|
||||
7 10 ł
|
||||
8 11 a
|
||||
9 12 ł
|
||||
10 14 a
|
||||
11 13 l
|
||||
12 14 y
|
||||
13 14 i
|
||||
14
|
||||
3
TaskD01/description.txt
Normal file
3
TaskD01/description.txt
Normal file
@ -0,0 +1,3 @@
|
||||
Write a program to find lines containing the word "Hamlet".
|
||||
Do use regular expressions.
|
||||
|
||||
0
TaskD01/shakespeare.exp
Normal file
0
TaskD01/shakespeare.exp
Normal file
0
TaskD01/shakespeare.in
Normal file
0
TaskD01/shakespeare.in
Normal file
2
TaskD01/simple.exp
Normal file
2
TaskD01/simple.exp
Normal file
@ -0,0 +1,2 @@
|
||||
Here comes Hamlet
|
||||
Hamlet Hamlet again
|
||||
3
TaskD01/simple.in
Normal file
3
TaskD01/simple.in
Normal file
@ -0,0 +1,3 @@
|
||||
Here comes Hamlet
|
||||
ABC
|
||||
Hamlet Hamlet again
|
||||
4
TaskD02/description.txt
Normal file
4
TaskD02/description.txt
Normal file
@ -0,0 +1,4 @@
|
||||
Write a program to find lines containing the word "pies" separated by spaces.
|
||||
The word does not need to have space on the left if it is the line beginning or space on the right if it is line ending.
|
||||
Return line no matter of word "pies" casing.
|
||||
Do use regular expressions.
|
||||
0
TaskD02/polish_wiki_excerpt.exp
Normal file
0
TaskD02/polish_wiki_excerpt.exp
Normal file
0
TaskD02/polish_wiki_excerpt.in
Normal file
0
TaskD02/polish_wiki_excerpt.in
Normal file
3
TaskD02/simple.exp
Normal file
3
TaskD02/simple.exp
Normal file
@ -0,0 +1,3 @@
|
||||
Pies ma Alę
|
||||
Kot i pies to zwierzęta
|
||||
pies
|
||||
5
TaskD02/simple.in
Normal file
5
TaskD02/simple.in
Normal file
@ -0,0 +1,5 @@
|
||||
Pies ma Alę
|
||||
Ala ma psa
|
||||
tu nic nie ma
|
||||
Kot i pies to zwierzęta
|
||||
pies
|
||||
4
TaskD03/description.txt
Normal file
4
TaskD03/description.txt
Normal file
@ -0,0 +1,4 @@
|
||||
Write a program to find lines containing date from 1900 to 1999 in format '19XX r.' no matter what on the left or right of the expression.
|
||||
Note that part ' r.' is obligatory.
|
||||
Do use regular expressions.
|
||||
|
||||
0
TaskD03/polish_wiki_excerpt.exp
Normal file
0
TaskD03/polish_wiki_excerpt.exp
Normal file
0
TaskD03/polish_wiki_excerpt.in
Normal file
0
TaskD03/polish_wiki_excerpt.in
Normal file
3
TaskD03/simple.exp
Normal file
3
TaskD03/simple.exp
Normal file
@ -0,0 +1,3 @@
|
||||
Kiedyś był 1934 r.
|
||||
Kiedyś był 1934 r.fsdfsdfsdf
|
||||
1934 r. to jakaś data
|
||||
5
TaskD03/simple.in
Normal file
5
TaskD03/simple.in
Normal file
@ -0,0 +1,5 @@
|
||||
Kiedyś był 1934 r.
|
||||
Kiedyś był 1934 r.fsdfsdfsdf
|
||||
Kiedyś był 1935 rok
|
||||
1934 r. to jakaś data
|
||||
1934 to też jakaś data
|
||||
3
TaskD04/description.txt
Normal file
3
TaskD04/description.txt
Normal file
@ -0,0 +1,3 @@
|
||||
Write a program to find all maximum substrings of digits.
|
||||
Return only these substrings separated by spaces in their order.
|
||||
Do use regular expressions.
|
||||
0
TaskD04/polish_wiki_excerpt.exp
Normal file
0
TaskD04/polish_wiki_excerpt.exp
Normal file
0
TaskD04/polish_wiki_excerpt.in
Normal file
0
TaskD04/polish_wiki_excerpt.in
Normal file
4
TaskD04/simple.exp
Normal file
4
TaskD04/simple.exp
Normal file
@ -0,0 +1,4 @@
|
||||
34234 34 5
|
||||
34535
|
||||
34
|
||||
1992 1999
|
||||
5
TaskD04/simple.in
Normal file
5
TaskD04/simple.in
Normal file
@ -0,0 +1,5 @@
|
||||
34234 34 dfd gfd 5
|
||||
34535
|
||||
fsdflskfjsdflk
|
||||
fsdkfj sdf34fdfd
|
||||
Firma powstała w 1992 r., z połączenia Authorware, Inc. (twórców pakietu Authorware) i MacroMind-Paracomp (producenta Macromind Director). W 1999 r. Macromedia zakupiła firmę Allaire i jej bi
|
||||
36
TaskE00/description.txt
Normal file
36
TaskE00/description.txt
Normal file
@ -0,0 +1,36 @@
|
||||
Liczby podzielne przez 5
|
||||
========================
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy zadany napis jest liczbą całkowitą
|
||||
podzielną przez 5. Napis nie powinien zawierać zer nieznaczących.
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string check, if the given string is an integer divisible by 5.
|
||||
The string should not contain leading zeros.
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 0.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 0.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 0/10
|
||||
10
TaskE00/test.exp
Normal file
10
TaskE00/test.exp
Normal file
@ -0,0 +1,10 @@
|
||||
yes
|
||||
yes
|
||||
no
|
||||
yes
|
||||
no
|
||||
no
|
||||
yes
|
||||
no
|
||||
yes
|
||||
no
|
||||
10
TaskE00/test.in
Normal file
10
TaskE00/test.in
Normal file
@ -0,0 +1,10 @@
|
||||
-1005
|
||||
-50
|
||||
-76
|
||||
0
|
||||
00
|
||||
01000
|
||||
1000
|
||||
353
|
||||
465
|
||||
@!q
|
||||
35
TaskE01/description.txt
Normal file
35
TaskE01/description.txt
Normal file
@ -0,0 +1,35 @@
|
||||
Liczby podzielne przez 25
|
||||
=========================
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy zadany napis jest dodatnią liczbą
|
||||
podzielną przez 25.
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string check, if the given string is a positive integer divisible by 25.
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 1.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 1.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 1/10
|
||||
8
TaskE01/test.exp
Normal file
8
TaskE01/test.exp
Normal file
@ -0,0 +1,8 @@
|
||||
no
|
||||
yes
|
||||
yes
|
||||
yes
|
||||
no
|
||||
no
|
||||
no
|
||||
no
|
||||
8
TaskE01/test.in
Normal file
8
TaskE01/test.in
Normal file
@ -0,0 +1,8 @@
|
||||
0
|
||||
1000
|
||||
111111125
|
||||
25
|
||||
353
|
||||
465
|
||||
@!q
|
||||
x50
|
||||
36
TaskE02/description.txt
Normal file
36
TaskE02/description.txt
Normal file
@ -0,0 +1,36 @@
|
||||
Kody pocztowe
|
||||
=============
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy wydobyć z kodu pocztowego kod miasta (2 pierwsze
|
||||
cyfry). Jeśli napis nie jest kodem pocztowym, należy wypisać "<NONE>".
|
||||
Zakładamy, że kod pocztowy składa się z 2 cyfr, minusa i 3 cyfr. Jeśli
|
||||
napis nie spełnia podanych warunków, należy wypisać "<NONE>".
|
||||
|
||||
For each string, extract the postal code of a city (2 first digits).
|
||||
If the string is not a postal code, you should print "<NONE>".
|
||||
We assume that the postal code consists of 2 digits, minus character, and 3 digits.
|
||||
If the string doesn't fulfill the condition, you should print "<NONE>".
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 2.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 2.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 2/10
|
||||
6
TaskE02/test.exp
Normal file
6
TaskE02/test.exp
Normal file
@ -0,0 +1,6 @@
|
||||
<NONE>
|
||||
<NONE>
|
||||
23
|
||||
<NONE>
|
||||
61
|
||||
<NONE>
|
||||
6
TaskE02/test.in
Normal file
6
TaskE02/test.in
Normal file
@ -0,0 +1,6 @@
|
||||
!@#$%^&
|
||||
0-333
|
||||
23-000
|
||||
61-23
|
||||
61-680
|
||||
BigFoot
|
||||
37
TaskE03/description.txt
Normal file
37
TaskE03/description.txt
Normal file
@ -0,0 +1,37 @@
|
||||
Numer NIP
|
||||
=========
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy napis jest numerem NIP zapisanym w
|
||||
formacie xxx-xxx-xx-xx bądź xxx-xx-xx-xxx. Nie trzeba brać pod uwagę sumy
|
||||
kontrolnej.
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string check, if the string is NIP number written in
|
||||
xxx-xxx-xx-xx bądź xxx-xx-xx-xxx format. You don't need to consider a checksum.
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 3.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 3.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 3/10
|
||||
5
TaskE03/test.exp
Normal file
5
TaskE03/test.exp
Normal file
@ -0,0 +1,5 @@
|
||||
yes
|
||||
yes
|
||||
yes
|
||||
no
|
||||
no
|
||||
5
TaskE03/test.in
Normal file
5
TaskE03/test.in
Normal file
@ -0,0 +1,5 @@
|
||||
000-00-00-000
|
||||
345-45-12-334
|
||||
345-455-12-34
|
||||
345-455-12-349
|
||||
3454551234
|
||||
37
TaskE04/description.txt
Normal file
37
TaskE04/description.txt
Normal file
@ -0,0 +1,37 @@
|
||||
Telefon filmowy
|
||||
===============
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy napis jest 9-cyfrowym numerem
|
||||
telefonu zapisanym w formacie "NNN-NNN-NNN" badź "NNN NNN NNN" zaczynającym
|
||||
sie od kombinacji "555".
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string, you should check, if the string is a 9-digit phone number
|
||||
written in "NNN-NNN-NNN" or "NNN NNN NNN" format, which starts with "555".
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 4.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 4.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 4/10
|
||||
12
TaskE04/test.exp
Normal file
12
TaskE04/test.exp
Normal file
@ -0,0 +1,12 @@
|
||||
no
|
||||
no
|
||||
no
|
||||
yes
|
||||
no
|
||||
yes
|
||||
no
|
||||
yes
|
||||
yes
|
||||
no
|
||||
no
|
||||
no
|
||||
12
TaskE04/test.in
Normal file
12
TaskE04/test.in
Normal file
@ -0,0 +1,12 @@
|
||||
055-555-555
|
||||
505-324-555
|
||||
551-233-455
|
||||
555 000 000
|
||||
555 000-000
|
||||
555 123 456
|
||||
555-000 000
|
||||
555-000-000
|
||||
555-123-456
|
||||
556 345 667
|
||||
556 345 6675
|
||||
556 345-667
|
||||
38
TaskE05/description.txt
Normal file
38
TaskE05/description.txt
Normal file
@ -0,0 +1,38 @@
|
||||
Akronim
|
||||
=======
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy napis jest akronimem (ciągiem co
|
||||
najmniej dwóch i co najwyżej pięciu wielkich liter. Dodatkowo należy
|
||||
uwzględnić akronimy "PCMCIA" i "WYSIWYG".
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string, check if the string is an acronym (sequence
|
||||
of at least 2 and at most 5 capital letters.
|
||||
Additionally, you should include acronyms "PCMCIA" i "WYSIWYG".
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 5.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 5.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 5/10
|
||||
11
TaskE05/test.exp
Normal file
11
TaskE05/test.exp
Normal file
@ -0,0 +1,11 @@
|
||||
no
|
||||
yes
|
||||
yes
|
||||
no
|
||||
yes
|
||||
yes
|
||||
no
|
||||
no
|
||||
no
|
||||
yes
|
||||
yes
|
||||
11
TaskE05/test.in
Normal file
11
TaskE05/test.in
Normal file
@ -0,0 +1,11 @@
|
||||
AAAAAA
|
||||
ABCDE
|
||||
ATX
|
||||
P
|
||||
PC
|
||||
PCMCIA
|
||||
PCMCIB
|
||||
Pc
|
||||
WYSIWYA
|
||||
WYSIWYG
|
||||
ZZZZ
|
||||
35
TaskE06/description.txt
Normal file
35
TaskE06/description.txt
Normal file
@ -0,0 +1,35 @@
|
||||
Liczba pięcio bądź sześciocyfrowa
|
||||
=================================
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy napis reprezentuje liczbę pięcio-
|
||||
bądź sześciocyfrową. Liczba nie powinna zawierać zer nieznaczących.
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string, check if the given string represents
|
||||
5 or 6 digits number. The number should not contain leading zeros.
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 6.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 6.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 6/10
|
||||
10
TaskE06/test.exp
Normal file
10
TaskE06/test.exp
Normal file
@ -0,0 +1,10 @@
|
||||
no
|
||||
no
|
||||
yes
|
||||
yes
|
||||
yes
|
||||
yes
|
||||
no
|
||||
no
|
||||
yes
|
||||
yes
|
||||
10
TaskE06/test.in
Normal file
10
TaskE06/test.in
Normal file
@ -0,0 +1,10 @@
|
||||
012345
|
||||
0123456
|
||||
10000
|
||||
100001
|
||||
12345
|
||||
123456
|
||||
333333333333
|
||||
9999
|
||||
99999
|
||||
999999
|
||||
35
TaskE07/description.txt
Normal file
35
TaskE07/description.txt
Normal file
@ -0,0 +1,35 @@
|
||||
Gwiazdek
|
||||
========
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy napis składa się z samych gwiazdek
|
||||
(co najmniej jednej).
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string, check if the given string consists of only asterisks (at least one).
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 7.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 7.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 7/10
|
||||
7
TaskE07/test.exp
Normal file
7
TaskE07/test.exp
Normal file
@ -0,0 +1,7 @@
|
||||
yes
|
||||
yes
|
||||
yes
|
||||
yes
|
||||
no
|
||||
no
|
||||
no
|
||||
7
TaskE07/test.in
Normal file
7
TaskE07/test.in
Normal file
@ -0,0 +1,7 @@
|
||||
*
|
||||
**
|
||||
***
|
||||
***********
|
||||
*a
|
||||
+
|
||||
a*
|
||||
38
TaskE08/description.txt
Normal file
38
TaskE08/description.txt
Normal file
@ -0,0 +1,38 @@
|
||||
Chichot
|
||||
=======
|
||||
|
||||
Napisać program, który wczytuje kolejne wiersze ze standardowego
|
||||
wejścia i analizuje każdy wiersz (bez znaku końca wiersza). Należy w
|
||||
jak największym stopniu wykorzystać wyrażenia regularne (np. nie wolno
|
||||
użyć negacji jako operacji w danym języku programowania, jeśli da się
|
||||
to wyrazić w samym wyrażeniu regularnym). Tam, gdzie to możliwe należy
|
||||
użyć pojedynczego wyrażenia regularnego.
|
||||
|
||||
Write a program, which loads consecutive lines from standard input
|
||||
and analyze every line (with no newline character). You should
|
||||
use regular expressions to the greatest extent possible (e.g. you
|
||||
can not use negation in the programming language if it is
|
||||
possible to express the same in regular expression). Wherever possible,
|
||||
use one regular expression.
|
||||
|
||||
Dla każdego napisu należy sprawdzić, czy napis jest chichotem tzn. "hi"
|
||||
powtórzonym przynajmniej 2 razy, po czym następuje opcjonalny ciąg
|
||||
wykrzykników.
|
||||
Jeśli napis spełnia tak określony warunek, należy wypisać na
|
||||
standardowym wyjściu 'yes', w przeciwnym razie — 'no'.
|
||||
|
||||
For each string, check if the given string consists of a sequence
|
||||
"hi" repeated at least 2 times followed by optional sequences of
|
||||
exclamation marks.
|
||||
If the string fulfills the condition, you should print 'yes' on the
|
||||
standard output and 'no' otherwise.
|
||||
|
||||
|
||||
UWAGA! Zadanie przeznaczone dla studentów, których numer indeksu
|
||||
dzieli się przez 10 z resztą 8.
|
||||
|
||||
Attention. The task is for students whose students id remainder of the division by 10 is 8.
|
||||
|
||||
POINTS: 1
|
||||
DEADLINE: 2021-12-04 23:59:59
|
||||
REMAINDER: 8/10
|
||||
Some files were not shown because too many files have changed in this diff Show More
Loading…
Reference in New Issue
Block a user