Traktor/myenv/Lib/site-packages/sympy/solvers/tests/test_numeric.py
2024-05-23 01:57:24 +02:00

140 lines
4.6 KiB
Python

from sympy.core.function import nfloat
from sympy.core.numbers import (Float, I, Rational, pi)
from sympy.core.relational import Eq
from sympy.core.symbol import (Symbol, symbols)
from sympy.functions.elementary.miscellaneous import sqrt
from sympy.functions.elementary.piecewise import Piecewise
from sympy.functions.elementary.trigonometric import sin
from sympy.integrals.integrals import Integral
from sympy.matrices.dense import Matrix
from mpmath import mnorm, mpf
from sympy.solvers import nsolve
from sympy.utilities.lambdify import lambdify
from sympy.testing.pytest import raises, XFAIL
from sympy.utilities.decorator import conserve_mpmath_dps
@XFAIL
def test_nsolve_fail():
x = symbols('x')
# Sometimes it is better to use the numerator (issue 4829)
# but sometimes it is not (issue 11768) so leave this to
# the discretion of the user
ans = nsolve(x**2/(1 - x)/(1 - 2*x)**2 - 100, x, 0)
assert ans > 0.46 and ans < 0.47
def test_nsolve_denominator():
x = symbols('x')
# Test that nsolve uses the full expression (numerator and denominator).
ans = nsolve((x**2 + 3*x + 2)/(x + 2), -2.1)
# The root -2 was divided out, so make sure we don't find it.
assert ans == -1.0
def test_nsolve():
# onedimensional
x = Symbol('x')
assert nsolve(sin(x), 2) - pi.evalf() < 1e-15
assert nsolve(Eq(2*x, 2), x, -10) == nsolve(2*x - 2, -10)
# Testing checks on number of inputs
raises(TypeError, lambda: nsolve(Eq(2*x, 2)))
raises(TypeError, lambda: nsolve(Eq(2*x, 2), x, 1, 2))
# multidimensional
x1 = Symbol('x1')
x2 = Symbol('x2')
f1 = 3 * x1**2 - 2 * x2**2 - 1
f2 = x1**2 - 2 * x1 + x2**2 + 2 * x2 - 8
f = Matrix((f1, f2)).T
F = lambdify((x1, x2), f.T, modules='mpmath')
for x0 in [(-1, 1), (1, -2), (4, 4), (-4, -4)]:
x = nsolve(f, (x1, x2), x0, tol=1.e-8)
assert mnorm(F(*x), 1) <= 1.e-10
# The Chinese mathematician Zhu Shijie was the very first to solve this
# nonlinear system 700 years ago (z was added to make it 3-dimensional)
x = Symbol('x')
y = Symbol('y')
z = Symbol('z')
f1 = -x + 2*y
f2 = (x**2 + x*(y**2 - 2) - 4*y) / (x + 4)
f3 = sqrt(x**2 + y**2)*z
f = Matrix((f1, f2, f3)).T
F = lambdify((x, y, z), f.T, modules='mpmath')
def getroot(x0):
root = nsolve(f, (x, y, z), x0)
assert mnorm(F(*root), 1) <= 1.e-8
return root
assert list(map(round, getroot((1, 1, 1)))) == [2, 1, 0]
assert nsolve([Eq(
f1, 0), Eq(f2, 0), Eq(f3, 0)], [x, y, z], (1, 1, 1)) # just see that it works
a = Symbol('a')
assert abs(nsolve(1/(0.001 + a)**3 - 6/(0.9 - a)**3, a, 0.3) -
mpf('0.31883011387318591')) < 1e-15
def test_issue_6408():
x = Symbol('x')
assert nsolve(Piecewise((x, x < 1), (x**2, True)), x, 2) == 0.0
def test_issue_6408_integral():
x, y = symbols('x y')
assert nsolve(Integral(x*y, (x, 0, 5)), y, 2) == 0.0
@conserve_mpmath_dps
def test_increased_dps():
# Issue 8564
import mpmath
mpmath.mp.dps = 128
x = Symbol('x')
e1 = x**2 - pi
q = nsolve(e1, x, 3.0)
assert abs(sqrt(pi).evalf(128) - q) < 1e-128
def test_nsolve_precision():
x, y = symbols('x y')
sol = nsolve(x**2 - pi, x, 3, prec=128)
assert abs(sqrt(pi).evalf(128) - sol) < 1e-128
assert isinstance(sol, Float)
sols = nsolve((y**2 - x, x**2 - pi), (x, y), (3, 3), prec=128)
assert isinstance(sols, Matrix)
assert sols.shape == (2, 1)
assert abs(sqrt(pi).evalf(128) - sols[0]) < 1e-128
assert abs(sqrt(sqrt(pi)).evalf(128) - sols[1]) < 1e-128
assert all(isinstance(i, Float) for i in sols)
def test_nsolve_complex():
x, y = symbols('x y')
assert nsolve(x**2 + 2, 1j) == sqrt(2.)*I
assert nsolve(x**2 + 2, I) == sqrt(2.)*I
assert nsolve([x**2 + 2, y**2 + 2], [x, y], [I, I]) == Matrix([sqrt(2.)*I, sqrt(2.)*I])
assert nsolve([x**2 + 2, y**2 + 2], [x, y], [I, I]) == Matrix([sqrt(2.)*I, sqrt(2.)*I])
def test_nsolve_dict_kwarg():
x, y = symbols('x y')
# one variable
assert nsolve(x**2 - 2, 1, dict = True) == \
[{x: sqrt(2.)}]
# one variable with complex solution
assert nsolve(x**2 + 2, I, dict = True) == \
[{x: sqrt(2.)*I}]
# two variables
assert nsolve([x**2 + y**2 - 5, x**2 - y**2 + 1], [x, y], [1, 1], dict = True) == \
[{x: sqrt(2.), y: sqrt(3.)}]
def test_nsolve_rational():
x = symbols('x')
assert nsolve(x - Rational(1, 3), 0, prec=100) == Rational(1, 3).evalf(100)
def test_issue_14950():
x = Matrix(symbols('t s'))
x0 = Matrix([17, 23])
eqn = x + x0
assert nsolve(eqn, x, x0) == nfloat(-x0)
assert nsolve(eqn.T, x.T, x0.T) == nfloat(-x0)