Rozwiązanie zadania "Ilorazy pierścienia wielomianów" #35
63
main.py
63
main.py
@ -33,8 +33,7 @@ class Poly:
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def __mul__(self, other):
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if self.int_mod != other.int_mod:
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raise Exception("Different modulo")
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assert self.int_mod == other.int_mod
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elements = {}
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@ -63,8 +62,7 @@ class Poly:
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def __add__(self, other):
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if self.int_mod != other.int_mod:
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raise Exception("Different modulo")
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assert self.int_mod == other.int_mod
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elements = self.elements.copy()
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@ -74,8 +72,29 @@ class Poly:
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else:
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elements[f] = other.elements[f]
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return Poly(self.int_mod,
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list(reversed(list(sorted(elements.values())))))
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els = {}
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for i in reversed(range(len(elements))):
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els[f"x{i}"] = elements[f"x{i}"]
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return Poly(self.int_mod, list(reversed(list(els.values()))))
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def __sub__(self, other):
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assert self.int_mod == other.int_mod
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elements = self.elements.copy()
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for e in other.elements:
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if e in elements:
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elements[e] -= other.elements[e]
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else:
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elements[e] = -other.elements[e]
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els = {}
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for i in reversed(range(len(elements))):
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els[f"x{i}"] = elements[f"x{i}"]
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return Poly(self.int_mod, list(reversed(list(els.values()))))
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def __truediv__(self, other):
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@ -134,24 +153,36 @@ if __name__ == "__main__":
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# print(c.elements)
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# print(c)
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# print(p ** 2)
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d = Poly(5, [-3, 1])
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# print(p)
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# print(d)
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# print(p)
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# print(p + d)
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d = Poly(5, [-3, 1])
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g = Poly(5, [1, 2, 1])
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print(d)
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print(g)
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print()
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# print()
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# print(g ** 2)
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print(d)
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print(g)
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# c = d * g
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print(g * d)
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print(d * g)
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print(g + d)
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# print(d)
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# print(g)
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# # c = d * g
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# print(g * d)
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# print(d * g)
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# print(g + d)
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# print(d + g)
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# print(d)
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# print(g)
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print(g - d)
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print(d - g)
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print()
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print(d + g)
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print(d)
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print(g)
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print(g + d)
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# print(d)
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# print(g)
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# print(g - d)
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# print(p / d)
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# print(p.elements[0])
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